僅在XSL 1.0中列出組中屬性的唯一值。

Question

當另一個屬性具有特定值時，需要列出組中屬性的唯一值。在XSL 1.0中進行這項工作非常難以理解。

感謝另一篇文章，我現在已經定義了分組，以便在屬性匹配特定條件時執行計數。然而，我很難僅列出一個特定屬性的唯一值，其中另一個屬性等於特定值，但僅限於當前組的成員內。

與往常一樣，這將對示例源數據和代碼更有意義。

下面是示例XML

<?xml version="1.0" encoding="UTF-8" standalone="yes"?> 
<Group1> 
    <Group2> 
    <LocationIdentification LocationID="0610390" /> 
    <LocationIdentification1 LocationQualifier="12" LocationID="USLGB"/> 
    </Group2> 
    <Group2> 
    <LocationIdentification LocationID="0610612" /> 
    <LocationIdentification1 LocationQualifier="12" LocationID="USLAX"/> 
    </Group2> 
    <Group2> 
    <LocationIdentification LocationID="0650004"/> 
    <LocationIdentification1 LocationQualifier="12" LocationID="USLGB"/> 
    </Group2> 
    <Group2> 
    <LocationIdentification LocationID="0650306"/> 
    <LocationIdentification1 LocationQualifier="6" LocationID="USLAX"/> 
    </Group2> 
    <Group2> 
    <LocationIdentification LocationID="0650220"/> 
    <LocationIdentification1 LocationQualifier="12" LocationID="USLGB"/> 
    </Group2> 
</Group1> 

我有XSL集合以創建基於從LocationIdentification節點屬性LocationID的前3個字符組。

XSL 1.0

<xsl:stylesheet version="1.0" 
<xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output method="html"/> 

<xsl:key name="grp" match="Group2" use="substring(LocationIdentification/@LocationID, 1, 3)"/> 

<xsl:template match="/Group1"> 
<table align="center" border="1"> 
    <thead> 
     <tr> 
      <th>Bay</th> 
      <th>Units</th> 
      <th>Locations</th> 
     </tr> 
    </thead> 
    <tbody> 
     <xsl:for-each select="Group2[generate-id()=generate-id(key('grp', substring(LocationIdentification/@LocationID, 1, 3))[1])]"> 
      <xsl:sort select="LocationIdentification/@LocationID"/> 
      <xsl:variable name="curr-key" select="substring(LocationIdentification/@LocationID, 1, 3)" />   
      <xsl:variable name="curr-group" select="key('grp', $curr-key)" /> 
      <tr> 
       <td> 
        <xsl:value-of select="$curr-key"/> 
       </td> 
       <td> 
        <xsl:value-of select="count($curr-group)"/> 
       </td> 
       <td> 
       <!-- NEW CODE NEEDS TO GO HERE --> 
       </td> 
      </tr> 
     </xsl:for-each> 
    </tbody> 
</table> 
</xsl:template> 

</xsl:stylesheet> 

我需要弄清楚，是如何內LocationIdentification1其中LocationQualifier = '12'

所需的輸出

<table align="center" border="1"> 
    <thead> 
    <tr> 
     <th>Bay</th> 
     <th>Count</th> 
     <th>Location(s)</th> 
    </tr> 
    </thead> 
    <tbody> 
    <tr> 
    <td>061</td> 
    <td>2</td> 
    <td>USLGB USLAX</td> 
    </tr> 
    <tr> 
    <td>065</td> 
    <td>3</td> 
    <td>USLGB</td> 
    </tr> 
</table> 

列出LocationID的獨特價值

請注意，Bay 65的計數爲3，但只有2 o f成員具有12的LocationQualifier，並且它們都具有相同的LocationID值，因此輸出結果應該只列出USLGB的位置。

Answer 1

你需要做的又一輪Muenchian分組的組成：再次

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output method="html"/> 

<xsl:key name="grp" match="Group2" use="substring(LocationIdentification/@LocationID, 1, 3)"/> 
<xsl:key name="loc12" match="LocationIdentification1[@LocationQualifier='12']" use="concat(substring(../LocationIdentification/@LocationID, 1, 3), '|', @LocationID)"/> 

<xsl:template match="/Group1"> 
    <table align="center" border="1"> 
     <thead> 
      <tr> 
       <th>Bay</th> 
       <th>Units</th> 
       <th>Locations</th> 
      </tr> 
     </thead> 
     <tbody> 
      <xsl:for-each select="Group2[generate-id()=generate-id(key('grp', substring(LocationIdentification/@LocationID, 1, 3))[1])]"> 
       <xsl:sort select="LocationIdentification/@LocationID"/> 
       <xsl:variable name="curr-key" select="substring(LocationIdentification/@LocationID, 1, 3)" />   
       <xsl:variable name="curr-group" select="key('grp', $curr-key)" /> 
       <tr> 
        <td> 
         <xsl:value-of select="$curr-key"/> 
        </td> 
        <td> 
         <xsl:value-of select="count($curr-group)"/> 
        </td> 
        <td> 
         <xsl:for-each select="$curr-group/LocationIdentification1[@LocationQualifier='12'][generate-id()=generate-id(key('loc12', concat($curr-key, '|', @LocationID))[1])]"> 
          <xsl:value-of select="@LocationID"/> 
          <xsl:text> </xsl:text> 
         </xsl:for-each> 
        </td> 
       </tr> 
      </xsl:for-each> 
     </tbody> 
    </table> 
</xsl:template> 

</xsl:stylesheet>