將變量值傳遞給另一個php文件？

Question

基本上，我有，你搜索項的頁面，查詢數據庫，這些條款都吐出含有查詢和分頁，像這樣：

1 2 [3] 4 5 

MATTHEW 1:18 
Now the birth of Jesus Christ was on this wise: When as his mother Mary was espoused to Joseph, before they came together, she was found with child of the Holy Ghost. 

MATTHEW 1:21 
And she shall bring forth a son, and thou shalt call his name JESUS: for he shall save his people from their sins. 

MATTHEW 1:25 
And knew her not till she had brought forth her firstborn son: and he called his name JESUS. 

這我已經完成了，下面我還沒有：

當我點擊「馬修」時，它應該在新頁面中列出「馬太福音」中的所有經文和章節，分頁。當我點擊返回（在瀏覽器中）時，它應該返回到前面的分頁結果集（上面），當我點擊向前（在瀏覽器中）時，它應該顯示所有詩句和東西的頁面從我點擊的聖經部分（馬修）。

我完全不知道如何開始任何這個。

Answer 1

描述的是當您的請求爲RESTful時瀏覽器的正常行爲。這僅僅意味着您包含了在請求本身中顯示正確頁面所需的全部信息。既然你在談論簡單的鏈接，這意味着你通過在URL中所需的信息：

http://example.com/verses.php?query=knew+her+not&page=3 
http://example.com/verses.php?book=matthew 

在你verses.php腳本，你檢查的$_GET['query']和/或$_GET['book']和$_GET['page']存在並檢索和輸出信息動態地基於這些變量。然後，您只需要生成適當的鏈接，並且瀏覽器會照顧後退/轉發行爲。