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我試圖保存一個可摺疊菜單的狀態,並使用jQuery Cookie插件..到目前爲止我遇到了麻煩..雖然..任何幫助嗎?用cookie和jquery保存UI狀態
,它的摺疊/展開
<script type="text/javascript">
$(document).ready(function() {
$(".login-holder > ul > .loginTitle").click(function() {
$(this).parent().find("li").slideToggle("fast");
if ($(this).parent().find(".toggle").html() == "+") {
$(this).parent().find(".toggle").html("-");
} else {
$(this).parent().find(".toggle").html("+");
}
});
})
</script>
XHTML的,我已經做到了這一點使用cookie
<ul class="account-links">
<div class="loginTitle">User Options<span class="toggle">-</span></div>
<div class="menuLinks">
<li>
<%= Html.ActionLink<EventController>(x => x.List(), "Events Near Me")%>
</li>
<li>
<%= Html.ActionLink<MyEventsController>(x => x.List(), "My Events")%>
</li>
<li>
<%= Html.ActionLink<AccountController>(x => x.Edit(), "My Profile")%>
</li>
<li>
<%= Html.ActionLink<ClubController>(x => x.List(), "Clubs Near Me")%>
</li>
<li>
<%= Html.ActionLink<MyClubsController>(x => x.List(), "My Clubs")%>
</li>
<li>
<%= Html.ActionLink<AccountController>(x => x.ChangePassword(), "Change My Password")%>
</li>
<li>
<%= Html.ActionLink<DependantController>(x => x.List(), "My Dependants") %>
</li>
</div>
</ul>
</div>
<% if (ViewModel.Profile.HasOrganizerInfo) { %>
<div class="login-holder">
<ul class="account-links">
<div class="loginTitle">Organizer Details<span class="toggle">-</span></div>
<div class=menuLinks>
<li>
<%= Html.ActionLink<AccountController>(x => x.Organizer(), "Organizer Details")%>
</li>
<li>
<%= Html.ActionLink<EventController>(x => x.Edit(default(int?)), "Post An Event")%>
</li>
<li>
<%= Html.ActionLink<EventAdminController>(x => x.List(), "Events Created By Me") %>
</li>
<li>
<%= Html.ActionLink<ClubController>(x => x.Edit(default(int?)), "Create A Club")%>
</li>
<li>
<%= Html.ActionLink<ClubAdminController>(x => x.List(), "Clubs Created By Me")%>
</li>
</div>
</ul>
</div>
<% } %>
我根本沒有在代碼中看到任何對cookie的引用,我是否錯過了一些東西?對於性能,可讀性和可維護性,您應該在本地存儲此引用:$(this).parent()。find(「。toggle」)(例如var foo =; foo.html())。 –
MightyE
2010-12-20 13:55:38
嗯,我有困難,所以我認爲我應該把一個乾淨的副本在那裏沒有參考,所以它沒有渾濁的情況 – Kevin 2010-12-20 13:57:46