mysql php獲取變量

Question

我想從mysql變量中獲取內容以用於php代碼，實際名稱（遊戲），url（遊戲）和alt（遊戲）。圖片網址和搜索數據庫正在工作。我很感激任何編碼方面的幫助。我不知道如何編寫指向名稱，url和alt的指針。

search_site.php

<link rel="shortcut icon" href="catchamouse3.png"> 

<link rel="stylesheet" type="text/css" href="homestyles2.css"> 

<link rel="stylesheet" type="text/css" href="submit.css"> 

<link rel="stylesheet" type="text/css" href="allflashgames(3).css"> 

<link rel="stylesheet" type="text/css" href="searchbar.css"> 

<link rel="stylesheet" type="text/css" href="styles2.css"> 

<?php 
include('func.php'); 

if(isset($_POST['keywords'])){ 
    $suffix = ""; 
    $keywords = mysql_real_escape_string(htmlentities(trim($_POST['keywords']))); 
    $errors = array(); 
    if(search_results($keywords) === false){ 
     $errors[] ='<h1>We didn\'t find anything for &quot;'.$keywords.'&quot;</h1>'; 
    } 
    if(empty($errors)){ 
     $results = search_results($keywords); 
     $results_num = count($results); 
     $suffix = ($results_num!=1)?'s':''; 
     echo '<h1>',$results_num,' item',$suffix,' For &quot;',$keywords,'&quot;</h1>'; 
     foreach($results as $result){ 
      echo ' 

<span class="overimage"> 

<a href="$game_url" target="_blank"> 

<span class="hoverimage"> 
<span class="hovertext1line-home">',$result['name'],'</span><img class="onlinegameimage-home" src="', 

$result['image_url'],'" alt=',$result['alt'],'> 
</span> 

</a> 

</span> 

'; 
     } 
    } 
    else{ 
     foreach($errors as $error){ 
      echo $error,'<br>'; 
     } 
    } 
} 
?> 

func.php

<?php 
    $con = mysql_connect('localhost','root',''); 
    mysql_select_db("my_search_test",$con); 

    function search_results($keywords){ 
     $returned_results = array(); 
     $where =""; 

     $keywords = preg_split('/[\s]+/',$keywords); 
     $total_keywords = count($keywords); 

     foreach($keywords as $key=>$keyword){ 
      $where .= "`keywords` LIKE '%$keyword%'"; 
      if($key != ($total_keywords -1)){ 
       $where .=" AND "; 
      } 
     } 
     $results = "SELECT name, image_url, game_url, alt FROM search_games WHERE $where"; 
     $results_num = ($results =mysql_query($results))? mysql_num_rows($results):0; 
     if($results_num === 0){ 
      return false; 
     } 
     else{ 
      while($results_row = mysql_fetch_assoc($results)){ 
       $returned_results[] = array(
        'image_url' => $results_row['image_url'] 

      ); 
     } 
     return $returned_results; 
    } 
} 
?> 

Answer 1

將它們添加到returned_results[]陣列就像你一樣image_url

while ($results_row = mysql_fetch_assoc($results)) { 
    $returned_results[] = array(
     'name' => $results_row['name'], 
     'image_url' => $results_row['image_url'], 
     'game_url' => $results_row['game_url'], 
     'alt' => $results_row['alt'] 
    ); 
} 

ADDED

每我的意見，這裏是寫你的邏輯更清潔，少冗餘的方式：

if (isset($_POST['keywords'])) { 
    // ... code 
    $results = search_results($keywords); 
    if ($results === false) { 
     echo '<h1>We didn\'t find anything for &quot;'.$keywords.'&quot;</h1>'; 
    } 
    else { 
     // we have results.. add rest of your code, ie. foreach(), etc. 
    } 
} 

Answer 2

<?php 
$con = mysql_connect('localhost','root',''); 
mysql_select_db("my_search_test",$con); 

function search_results($keywords){ 
    $returned_results = array(); 
    $where =""; 

    $keywords = preg_split('/[\s]+/',$keywords); 
    $total_keywords = count($keywords); 

    foreach($keywords as $key=>$keyword){ 
     $where .= "`keywords` LIKE '%$keyword%'"; 
     if($key != ($total_keywords -1)){ 
      $where .=" AND "; 
     } 
    } 
    $results = "SELECT name, image_url, game_url, alt FROM search_games WHERE $where"; 
    $results_num = ($results =mysql_query($results))? mysql_num_rows($results):0; 
    if($results_num === 0){ 
     return false; 
    } 
    else{ 
     while($results_row = mysql_fetch_assoc($results)){ 
      $returned_results[] = array(
       'image_url' => $results_row['image_url'] 

      ); 
     } 
     return $returned_results; 
    } 
} 
?> 

你射擊search_results（$關鍵字）在這裏兩次。首先在if（false（$ errors））塊中檢查=== false和second。這是多餘的。調用search_results（$ keywords）一次，存儲結果並在需要的地方使用結果。