1
那麼,我有一個表生成器,與MySQL數據庫。有語法錯誤,但不知道在哪裏
首先,代碼:
PHP
while($result = mysqli_fetch_assoc($SQL)){
$tbl->addCell("<p onBlur = 'editTable(" . $result['id_user'] . ", this, 'Name')' contentEditable = 'true'>" . $result['Name'] . "</p>");
$tbl->addCell("<p onBlur = 'editTable(" . $result['id_user'] . ", this, 'Username')' contentEditable = 'true'>" . $result['Username'] . "</p>");
$tbl->addCell("<p onBlur = 'editTable(" . $result['id_user'] . ", this, 'Email')' contentEditable = 'true'>" . $result['Email'] . "</p>");
$tbl->addCell("<p onBlur = 'editTable(" . $result['id_user'] . ", this, 'Grade')' contentEditable = 'true'>" . $result['Grade'] . "</p>");
$tbl->addCell("<input type = 'button' class = 'Edit-TBB' value = 'Edit'>
<input type = 'button' class = 'Delete-TBB' value = 'Delete'>");
$tbl->addRow();
}
AJAX
function editTable(id, new_text, column) {
$.ajax({
url: "../PHP/Configuracion/edit_grade.php",
type: "POST",
data: 'id='+id+'&text='+new_text.innerText,
success: function(data){
alert(column);
}
});
}
這裏的問題是:
我有這個'editTable(" . $result['id_user'] . ", this, 'Name')'
如果我在Chrome中更改代碼像this ......它的工作原理,但我不知道我需要在代碼編輯器來改變。
我需要改變什麼?
謝謝!
嘗試在HTML中使用雙引號的onblur價值,像你這樣,通過與他們逃脫「\」。 – georgiaboy82