Laravel5.1查詢關係（雄辯ORM）

Question

我的模型是患者 - >的Sample-> Ready_Sample，關係都是一對多， 我的問題是我查詢Ready_Sample需要知道patient.name

Patient_Model

class Patient_Model extends Base_Model { 

    protected $table = 'patients'; 

    public function samples(){ 
     return $this->hasMany('App\Models\Sample_Model','patient_id','code'); 
    } 
} 

Sample_Model

class Sample_Model extends Base_Model{ 

    protected $table = 'samples'; 

    public function patient(){ 
     return $this->belongsTo('App\Models\Patient_Model','patient_id','code'); 
    } 

    public function ready_samples(){ 
     return $this->hasMany('App\Models\Ready_Sample_Model','sample_id','code'); 
    } 
} 

Ready_Sample_Model

class Ready_Sample_Model extends Model{ 

    protected $table = 'ready_samples'; 

    public function sample(){ 
     return $this->belongsTo('App\Models\Sample_Model','sample_id','code'); 
    } 
} 

在Sample_Controller

class Sample_Controller extends Controller{ 

    public function query(Request $request){ 

    $result = Sample_Model::with(['patient']); 
     ->orderBy("updated_at","desc") 
     ->Paginate(15) 
     ->toJson(); 
    return $result; 
} 

在樣品我知道拿到patient.name，但Ready_Sample如何獲得Patien.name？

Answer 1

您可以通過下面的代碼獲得patient.name：

$readySample = Ready_Sample_Model::first(); // fetch the first record 

echo $readySample->sample->patient->name; 

希望它能幫助！