我需要一些幫助來更新使用沙發數據庫。我在我的頁面上有一項任務。如果用戶點擊類似的,那麼應該在我的couchbase桶中更新點數。我已經嘗試過自己的更新處理程序代碼,但有一些時間延遲。我的更新代碼也包含在下面。更新沙發數據庫
這是我喜歡一個任務代碼...
public ResponseVO LikeTask(LikeVO likeVO)
{
ResponseVO response = new ResponseVO();
try
{
if (!isLiked(likeVO.TaskID, likeVO.UserID))
{
UpdateTaskDB likeUpdate = new UpdateTaskDB();
UpdateTaskVO updatetaskvo = new UpdateTaskVO();
updatetaskvo.FieldName = "Likes";
LikeVO tempvo = new LikeVO();
tempvo.LikedOn = DateTime.Now.ToString();
tempvo.UserID = likeVO.UserID;
tempvo.UserName = likeVO.UserName;
tempvo.TaskID = likeVO.TaskID;
updatetaskvo.ObjectValue = tempvo;
updatetaskvo.TaskID = likeVO.TaskID;
likeUpdate.UpdateDocument(updatetaskvo);
}
response.StatusMessage = "Liked Successfully";
}
catch (Exception ex)
{
response.StatusCode = "0";
response.StatusMessage = ex.Message;
}
return response;
}
我自己的更新處理器代碼:
public class UpdateTaskDB
{
CouchbaseClient oCouchbase;
public UpdateTaskDB()
{
oCouchbase = new CouchbaseClient("vwspace", "");
}
public TaskVO GetTaskByID(string task_id)
{
TaskVO results = null;
try
{
String str1;
str1 = (String)oCouchbase.Get(task_id);
results = JsonConvert.DeserializeObject<TaskVO>(str1);
}
catch (Exception ex)
{
}
return results;
}
public void UpdateDocument(UpdateTaskVO inputParams)
{
try
{
var client = new CouchbaseClient("vwspace", "");
TaskVO taskDoc = GetTaskByID(inputParams.TaskID);
switch (inputParams.FieldName)
{
case "Likes":
List<LikeVO> docLikes = taskDoc.likes;
docLikes.Add((LikeVO)inputParams.ObjectValue);
taskDoc.likes = docLikes;
break;
case "UnLike":
LikeVO unlikevo = (LikeVO)inputParams.ObjectValue;
for (int count = 0; count < taskDoc.likes.Count; count++)
{
if (taskDoc.likes[count].UserID.Equals(unlikevo.UserID))
{
unlikevo = taskDoc.likes[count];
break;
}
}
taskDoc.likes.Remove(unlikevo);
break;
default:
break;
}
String json = JsonConvert.SerializeObject(taskDoc);
client.Store(StoreMode.Set, inputParams.TaskID, json);
}
catch (Exception ex)
{
Console.Write("Exception :" + ex.Message);
}
}
}
療法是任何其他方式來處理couchbase此更新?請幫助我..
results.Cas = getResult.Cas; 這裏result.Cas是不可訪問的,因爲它被鑄造爲 ... –
Xavier
正確 - 我在代碼片段中有一條評論,提示您必須添加一個Cas屬性或一些其他機制(out參數或Tuple可能?)通過Cas。 –