jQuery(function ($) {
/* fetch elements and stop form event */
$("form.follow-form").submit(function (e) {
/* stop event */
e.preventDefault();
/* "on request" */
$(this).find('i').addClass('active');
/* send ajax request */
$.post('recycle.php', {
followID: $(this).find('input').val()
}, function() {
/* find and hide button, create element */
$(e.currentTarget)
.find('button').hide()
.after('<span class="following"><span></span>Following!</span>');
});
});
});
的HTML:我的jquery ajax請求沒有訪問數據庫?
<form class="follow-form" method="post" action="recycle.php">
<input name="id" value="$id" type="hidden">
<input name="$tweet" value="$tweet" type="hidden">
<button type="submit" value="Actions" class="btn follow" title="123456">
<i></i><span>recyle</span>
</button>
</form>
reycle.php:
<?php session_start();
include_once ('includes/connect.php');
$id = $_POST['id'];
$tweet =$_POST['tweet'];
$registerlistener = mysql_query("INSERT INTO notes (user_id, user_note,recyle_id,dt) VALUES('".$_SESSION['user_id']."','".$tweet."','".$id."',NOW()");
?>
的問題是,它不是訪問recycle.php文件,插入HTML表單的信息到數據庫!但它正在做整個jQuery動畫!我沒有看到最新的問題!
什麼是「整個jQuery動畫」? – elektronikLexikon 2010-09-17 17:02:40
基本上當我點擊reycle按鈕時,它變成了文字說「回收」 – getaway 2010-09-17 17:04:05
該值'=「$ id」'不是'value =「<?php echo $ id?>」',並且與$ tweet相同' – RobertPitt 2010-09-17 17:36:16