的Python，加txt文件的項目到一個列表

Question

說我有一個空列表myNames = []

我怎樣可以打開一個文件，每行名稱，在每個名字讀入名單？

，如：

>  names.txt 
>  dave 
>  jeff 
>  ted 
>  myNames = [dave,jeff,ted] 

Answer 1

閱讀documentation：

with open('names.txt', 'r') as f: 
    myNames = f.readlines() 

已經提供的答案是怎麼別人擺脫換行符。

更新：

Fred Larson提供了在他的評論一個很好的解決方案：

with open('names.txt', 'r') as f: 
    myNames = [line.strip() for line in f] 

Answer 2

f = open('file.txt','r') 

for line in f: 
    myNames.append(line.strip()) # We don't want newlines in our list, do we? 

Answer 3

Names = [] 
for line in open('names.txt','r').readlines(): 
    Names.append(line.strip()) 

條（）之前和之後的字符串切空間...

Answer 4

names=[line.strip() for line in open('names.txt')] 

Answer 5

#function call 
read_names(names.txt) 
#function def 
def read_names(filename): 
with open(filename, 'r') as fileopen: 
    name_list = [line.strip() for line in fileopen] 
    print (name_list) 

Answer 6

這應該是在地圖和lambda

with open ('names.txt','r') as f : 
    Names = map (lambda x : x.strip(),f_in.readlines()) 

我指正（或至少改善）了良好的情況下。 List內涵是更優雅

with open ('names.txt','r') as f : 
    Names = [name.rstrip() for name in f] 

Answer 7

讀取一個文件，並把每行列表中的Python的方式：

from __future__ import with_statement #for python 2.5 
Names = [] 
with open('C:/path/txtfile.txt', 'r') as f: 
    lines = f.readlines() 
    Names.append(lines.strip())