字母變更代碼

Question

該腳本需要一個句子並對其進行編碼。代碼採用給定單詞中的每個字母，並按照單詞的長度在字母表中將其顛倒。所以「貓」變成「fwd」，「小」變成「xrfqq」，「小貓」變成「xrfgg fwd」。

我想看看是否有什麼我應該做的不同，或者如果你們有一些改進建議。

#Letter altering code 

alphabet = ["a","b","c","d","e","f","g","h","i","j", 
     "k","l","m","n","o","p","q","r","s","t", 
     "u","v","w","x","y","z"] 

textIn= "" 

while textIn.lower != 'q': 
    textIn = input("Type a sentence to be translated ('q' to quit).\n"\ 
       ).lower() 
    textOut = "" 

if textIn == 'q': 
    break 
else: 
    for word in textIn.split(): 
     newWord = "" 
     for char in word: 
      if char in alphabet: 
       pos = alphabet.index(char) 
       newPos = (pos + len(word))%26 
       newChar = alphabet[newPos] 
       newWord += newChar 

      else: 
       newWord += char 

     textOut += newWord + " " 

print(textOut) 

Answer 1

這很不錯。

alphabet是string.ascii_lowercase

textIn.lower應textIn.lower()

break應僅在一個循環中使用。你想pass，這意味着'無所事事'。

將新字符添加到新單詞的循環很清楚。我喜歡。然而，還有其他一些比較細緻的方法可以做到，它們更加pythonic並且仍然可以清楚。