2016-11-10 118 views
0

我需要我的字符串轉換,使其製作成特殊格式轉換爲字符串,刪除特殊字符和更換

例如:

string = "the cow's milk is a-okay!" 

converted string = "the-cows-milk-is-a-okay" 
+1

聽起來不錯。試過什麼了嗎? –

+0

這可能是''''join(s.split())',但符號移除要求會使其變得模糊 –

+1

看看[String slugification in Python](http://stackoverflow.com/questions/5574042/string- slugification-in-python) –

回答

0
import re 

s = "the cow's milk is a-okay!" 
s = re.sub(r'[^a-zA-Z\s-]+', '', s) # remove anything that isn't a letter, space, or hyphen 
s = re.sub(r'\s+', '-', s) # replace all spaces with hyphens 
print(s) # the-cows-milk-is-a-okay 

這裏一個「空間」是任何包含製表符和換行符的空白字符。要更改此設置,請將\s替換爲實際空格字符

多個空格的運行將被替換爲一個連字符。要更改此設置,請在第二次撥打re.sub時刪除+

+0

中的「 - 」再次加入字符串'\ W +'會更好嗎? –

+2

@ cricket_007不,這不適用於空格,連字符或下劃線。 –

+0

@AlexHall非常感謝!我真的必須重新研究這個。 –

0

這個怎麼樣(缺點是無法維持的連字符-),

import string 

s = "the cow's milk is a-okay!" 

table = string.maketrans(" ", "-") 
new_s = s.translate(table, string.punctuation) 

print(new_s) 
# the-cows-milk-is-aokay 
+0

這不是OP想要的。具有諷刺意味的是,你承認在你的答案。 –

0
>>> string = "the cow's milk is a-okay!" 
>>> string 
"the cow's milk is a-okay!" 
>>> string = string.replace(' ','-') 
>>> for char in string: 
...  if char in "?.!:;/'": 
...    string = string.replace(char,'') 
... 
>>> string 
'the-cows-milk-is-a-okay' 
0

一個簡單的生成器表達式可以用來實現這一點:

>>> s = "the cow's milk is a-okay!" 
>>> ''.join(('-' if el == " " else el if el not in "?.!:;/'" else "" for el in s)) 
'the-cows-milk-is-a-okay' 
>>>