我有一個倒計時器,在Chrome或Firefox中查看時按預期工作。但是,在Safari中查看時有錯誤。Javascript倒數計時器在Safari中不工作
下面的代碼:
!function(e) {
e.fn.countdown = function(t, n) {
function s() {
if (eventDate = Date.parse(o.date)/1e3, currentDate = Math.floor(e.now()/1e3), currentDate >= eventDate) {
if ("undefined" === n || null == n)
return !1;
n.call(this), clearInterval(interval)
}
seconds = eventDate - currentDate,
days = Math.floor(seconds/86400),
seconds -= 60 * days * 60 * 24,
hours = Math.floor(seconds/3600),
seconds -= 60 * hours * 60,
minutes = Math.floor(seconds/60),
seconds -= 60 * minutes,
a.find(".timeRefDays").text(1 == days ? "day" : "days"),
a.find(".timeRefHours").text(1 == hours ? "hour" : "hours"),
a.find(".timeRefMinutes").text(1 == minutes ? "minute" : "minutes"),
a.find(".timeRefSeconds").text(1 == seconds ? "second" : "seconds"),
"on" == o.format && (days = String(days).length >= 2 ? days : "0" + days, hours = String(hours).length >= 2 ? hours : "0" + hours, minutes = String(minutes).length >= 2 ? minutes : "0" + minutes, seconds = String(seconds).length >= 2 ? seconds : "0" + seconds),
isNaN(eventDate) ? (alert("Invalid date. Here's an example: 12 Tuesday 2015 17:30:00"), clearInterval(interval)) : (a.find("> li .days").text(days), a.find("> li .hours").text(hours), a.find("> li .minutes").text(minutes), a.find("> li .seconds").text(seconds))
}
var a = jQuery(this), o = {
date: null,
format: null
};
t && e.extend(o, t), s(), interval = setInterval(s, 1e3)
}
在Safari瀏覽器控制檯中的錯誤信息是: 「找不到變量:間隔」
爲什麼不是在Safari這方面的工作?
在分配'interval = setInterval(s,1e3)'之前,您正在調用's()'。 – Barmar