Php在日期合併陣列

Question

我有兩個數組，我試圖根據它們的日期進行合併。這裏是陣列的樣子：

$a[0][0] = '11/15/08'; 
$a[0][1] = '50'; 
$a[1][0] = '11/20/08'; 
$a[1][1] = '75'; 
$a[2][0] = '01/04/09'; 
$a[2][1] = '23'; 
$a[3][0] = '01/09/09'; 
$a[3][1] = '92'; 

和

$b[0][0] = '01/04/09'; 
$b[0][1] = '30'; 
$b[1][0] = '01/05/09'; 
$b[1][1] = '54'; 
$b[2][0] = '01/08/09'; 
$b[2][1] = '89'; 
$b[3][0] = '01/09/09'; 
$a[3][1] = '62'; 

在我希望的合併結束：

$n[0][0] = '11/15/08'; 
$n[0][1] = '50'; 
$n[0][2] = '0'; 
$n[1][0] = '11/20/08'; 
$n[1][1] = '75'; 
$n[1][2] = '0'; 
$n[2][0] = '01/04/09'; 
$n[2][1] = '23'; 
$n[2][2] = '30'; 
$n[3][0] = '01/05/09'; 
$n[3][1] = '0'; 
$n[3][2] = '54'; 
$n[4][0] = '01/08/09'; 
$n[4][1] = '0'; 
$n[4][2] = '89'; 
$n[4][0] = '01/09/09'; 
$n[4][1] = '92'; 
$n[4][2] = '62'; 

這可能嗎？

Answer 1

我會首先將數組排序爲一個具有時間戳作爲其鍵和數組數組作爲其值。這將很容易分類。例如：

$result = array(); 
foreach (array_merge($a, $b) as $item) { 
    $date = $item[0]; 
    $dateParts = explode('/', $date); 
    $timestamp = mktime(0,0,0,$dateParts[0], $dateParts[1], $dateParts[2]); 
    if (!isset($result[$timestamp])) { 
     $result[$timestamp] = array(); 
    } 

    $result[$timestamp][] = $item[1]; 
} 

由於鍵是日期時間戳，我們可以很容易地按日期排序的數組：

ksort($result); 

然後我們就可以在陣列轉換成格式，你想讓它

$result2 = array(); 
foreach ($result as $timestamp => $item) { 
    $tmp = array(); 

    $tmp[] = date('m/d/y', $timestamp); 
    $tmp = array_merge($tmp, $item); 
    $result2[] = $tmp; 
} 

print_r($result2); 

Answer 2

最簡單的方法是使用日期索引

#Initialization 

    $n = array(); 
    $n[$date] = array(); 
    $n[$date][0] = ""; 
    $n[$date][1] = ""; 

    #and then 

    $n["10/01/09"][0] = "10"; 
    $n["10/01/09"][1] = "50"; 
    $n["11/02/09"][1] = "70"; 
    $n["01/05/09"][0] = "90"; 

---編輯

你可以看到在「array_merge」，「array_combine」，這個功能...但在這種情況下，這可以解決

Answer 3

這是我的解決方案：

$a[0][0] = '11/15/08'; 
$a[0][1] = '50'; 
$a[1][0] = '11/20/08'; 
$a[1][1] = '75'; 
$a[2][0] = '01/04/09'; 
$a[2][1] = '23'; 
$a[3][0] = '01/09/09'; 
$a[3][1] = '92'; 

$b[0][0] = '01/04/09'; 
$b[0][1] = '30'; 
$b[1][0] = '01/05/09'; 
$b[1][1] = '54'; 
$b[2][0] = '01/08/09'; 
$b[2][1] = '89'; 
$b[3][0] = '01/09/09'; 
$b[3][1] = '62'; 

function dates($arr, &$result) 
{ 
    foreach ($arr as $dates) 
    { 
     $result[$dates[0]][] = $dates[1]; 
    } 
} 

$result = array(); 
dates($a, $result); 
dates($b, $result); 

$dates = array(); 
$i = 0; 
foreach ($result as $date => $res) 
{ 
    $dates[$i][0] = $date; 
    $dates[$i][1] = $res[0]; 
    if (count($res) == 1) 
    { 
     $dates[$i][2] = 0; 
    } else { 
     $dates[$i][2] = $res[1]; 
    } 
    $i++; 
} 
print_r($dates); 

輸出：

Array 
(
    [0] => Array 
     (
      [0] => 11/15/08 
      [1] => 50 
      [2] => 0 
     ) 

    [1] => Array 
     (
      [0] => 11/20/08 
      [1] => 75 
      [2] => 0 
     ) 

    [2] => Array 
     (
      [0] => 01/04/09 
      [1] => 23 
      [2] => 30 
     ) 

    [3] => Array 
     (
      [0] => 01/09/09 
      [1] => 92 
      [2] => 62 
     ) 

    [4] => Array 
     (
      [0] => 01/05/09 
      [1] => 54 
      [2] => 0 
     ) 

    [5] => Array 
     (
      [0] => 01/08/09 
      [1] => 89 
      [2] => 0 
     ) 

)