函數的多個參數定義Python

我正在嘗試編寫一個函數來計算貸款的成本，但我不斷得到貸款的成本爲用戶輸入的負值貸款。函數的多個參數定義Python

#define monthly payment 
def MonthlyPayment (ammountOfLoan, numberOfPeriods,yearlyInterestRate): 
    ammountOfLoan = 0 
    numberOfPeriods = 0 
    yearlyInterestRate = 0 
    payment = [(yearlyInterestRate/12)/(1-(1+yearlyInterestRate/12))**(-numberOfPeriods)] * ammountOfLoan  
    return (payment) 


#define cost of loan  
def LoanCost(principal, month, payment): 
    period = 0 
    month = 0 
    payment = 0 
    cost = period * payment - principal 
    return (cost) 

#calculate cost of loan 
def main(): 
    loan = float(raw_input("What is the ammount of your loan? ")) 
    period = float(raw_input("How many months will you make payments? ")) 
    rate = float(raw_input("What is the interest rate? ")) 
    rate = rate/100 
    MonthlyPayment(loan, period, rate) 
    costOfLoan = LoanCost(loan, period, rate) 
    print "The cost of the loan is $" + str(costOfLoan) 

#run main 
main()

來源

2014-03-28 user3471046

'pdb'是你的朋友 – shx2

爲什麼你會傳遞參數，如果你只是立即放棄他們的價值觀？（例如通過執行'numberOfPeriods = 0'）。你應該真的瞭解python的基礎知識。只需閱讀教程，文檔，以艱難的方式學習python，編碼學院，任何東西。 – acushner

LoanCost被設定期限和付款爲0（你正在做的MonthlyPayment同樣的錯誤，也一樣），然後乘以他們。所以你以（0 * 0） - principal爲結束。當你真正的意思是「期間」時，你也會調用第二個參數「月」。

只是爲了澄清，當你有一個函數定義，就像

def func(a, b, c):

你不應該在函數體中初始化，b和c爲零。當你這樣做時，你正在覆蓋他們的價值。只需直接使用它們。

來源

2014-03-28 16:49:01 dano

函數的多個參數定義Python

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