獲取渲染參數錯誤：什麼是正確的語法或用法？

我是Ruby，Sinatra和Pusher的新手，所以這是一個基本問題。我試圖驗證推送客戶端（使用iOS演示代碼https://github.com/lukeredpath/libPusher）。下面的服務器代碼失敗，錯誤時的iOS客戶端嘗試加入一個存在通道：獲取渲染參數錯誤：什麼是正確的語法或用法？

ArgumentError - wrong number of arguments (1 for 2): 
    /Users/waveocean/.rvm/gems/ruby-1.9.3-p327/gems/sinatra-1.3.3/lib/sinatra/base.rb:665:in `render' 
    web.rb:13:in `auth' 
    web.rb:26:in `block in <main>' 
    /Users/waveocean/.rvm/gems/ruby-1.9.3-p327/gems/sinatra-1.3.3/lib/sinatra/base.rb:1265:in `call' 

... snipped for brevity ...

下面是代碼：

require 'sinatra' 
require 'pusher' 
require 'thin' 
Thin::HTTP_STATUS_CODES[403] = "FORBIDDEN" 

Pusher.app_id = 'MY-APP-ID' 
Pusher.key = 'MY-KEY' 
Pusher.secret = 'MY-SECRET' 

def auth 
    response = Pusher[params[:channel_name]].authenticate(params[:socket_id], {:user_id => 101}) 
    render :json => response 
end 

use Rack::Auth::Basic, "Protected Area" do |username, password| 
    username == 'foo' && password == 'bar' 
end 

post '/presence/auth' do 
    if params[:channel_name] == 'presence-demo' 
     auth 
    else 
    # render :text => "Forbidden", :status => '403' 
    response.status = 403 
    end 
end

有人能提供建議或渲染的正確使用？

來源

2012-12-19 vmanjz

這是我發現的。 render與Rails關聯，而不是嚴格的Ruby。爲了給西納特拉路線迴應，請使用身份驗證方法如下：

def auth 
    response = Pusher[params[:channel_name]].authenticate(params[:socket_id], {:user_id => 101}) 
    [200, {"Content-Type" => "application/json"}, response.to_json] 
end

事實證明，推動iOS的項目演示提供了所需的實施腳本/ auth_server.rb文件。這裏有安裝說明文檔：https://github.com/lukeredpath/libPusher/wiki/Adding-libPusher-to-your-project。

來源

2012-12-19 17:37:11 vmanjz

獲取渲染參數錯誤：什麼是正確的語法或用法？

回答

相關問題