IF-Else循環在android中使用來比較字符串與EditText？

Question

This If Else does not work因此不直接進入菜單頁面。我想比較字符串與EditText輸入，所以我將其更改爲字符串。我如何比較這兩個領域的字符串輸入，並將它們與我的字符串的if-else循環比較和啓動意圖

package mjour.fyp; 

     public class Login extends Activity{ 

EditText username; 
EditText password; 
Button login; 
String name, pass; 
String lname = "mehdi"; 



public void onCreate(Bundle savedInstanceState) { 
    // TODO Auto-generated method stub 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.userlogin); 

    login = (Button) findViewById(R.id.blog); 
    username = (EditText) findViewById(R.id.editText1); 
    name = username.getText().toString(); 
    password = (EditText) findViewById(R.id.editText2); 
    pass = password.getText().toString(); 

    login.setOnTouchListener(new OnTouchListener() { 

     public boolean onTouch(View v, MotionEvent event) { 
      // TODO Auto-generated method stub 

      Intent myintent = new Intent("mjour.fyp.MENU"); 
      if(name.contentEquals(lname)) 
      startActivity(myintent); 

      return false; 

    };});}} 

Answer 1

是否缺少其他的startActivity後（）？