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所以我有這個小項目,我在那裏做馬里奧跳。但我無法弄清楚如何重新繪製它。如果我在點擊後在主類中做了這個動作,那麼整個跳躍將會非常生澀。不知道如何重畫
我試圖在我的跳轉功能結束時做到這一點,但這並沒有奏效。
這裏是我的代碼:
主營:
package klassid;
import java.awt.Color;
import java.awt.Graphics;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.event.KeyEvent;
import java.awt.event.KeyListener;
import javax.swing.JComponent;
import javax.swing.JFrame;
import javax.swing.Timer;
public class Main extends JComponent implements KeyListener, ActionListener{
static Hero hero;
Timer t = new Timer(500,this);
public static void main(String[] args) {
JFrame aken = new JFrame("Simple jumping simulator");
aken.setSize(600, 600);
aken.getContentPane().setBackground(new Color(255,255,255));
aken.getContentPane().add(new Main());
aken.setVisible(true);
aken.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
hero.the_jump();
}
public Main(){
addKeyListener(this);
setFocusable(true);
t.start();
hero = new Hero(0, 320);
}
public void paintComponent(Graphics g){
hero.render(g, this);
g.setColor(Color.GREEN);
g.fillRect(0, 550, 600, 2);
}
@Override
public void keyPressed(KeyEvent e) {
hero.move(e.getKeyCode());
}
public void keyReleased(KeyEvent e) {
hero.move2(e.getKeyCode());
}
public void keyTyped(KeyEvent e) {}
public void actionPerformed(ActionEvent e) {}
}
我的英雄職業:
package klassid;
import java.awt.Toolkit;
import java.awt.Image;
import java.awt.Graphics;
public class Hero {
static Main main;
int y;
Image pilt = Toolkit.getDefaultToolkit().getImage("../mario.png");
private double height = 0, speed = 4;
public static final double gravity = 9.81;
private double x = 25;
private boolean left = false, right = false, up = false;
public Hero(int x, int y){
this.x = x;
this.y = y;
}
public void render(Graphics g, Main pohiKlass){
g.drawImage(pilt, (int) (x), (int) (500-(height*100)), 50, 50, pohiKlass);
}
public void the_jump() {
long previous = 0, start = 0;
while(true){
start= System.nanoTime();
if(previous != 0 && up){
double delta = start - previous;
height += (delta/1000000000) * speed;
speed -= (delta/1000000000) * gravity;
}
if(left)
x -= 3;
if(right)
x += 3;
try {
Thread.sleep(10);
} catch (InterruptedException e) {
e.printStackTrace();
}
if(height < 0){
height = 0;
speed = 4;
up = false;
}
previous = start;
repaint();
}
}
public void move(int i){
if(i == 38)
up=true;
if(i == 37)
left=true;
if(i == 39)
right=true;
}
public void move2(int i){
if(i == 37)
left=false;
if(i == 39)
right=false;
}
}
我也試圖訪問的paintComponent在the_jump功能,但它並沒有爲工作我不知道它期望什麼樣的參數。
這個混亂是如何解決的?
如果我循環重繪這麼多次,這是一個巨大的性能打擊嗎? – Veske
以圖形方式在CPU上做任何事情都不理想。我會建議測試它,看看它是否在性能範圍內。您可以隨時使用計時器值進行微調(33可能是一個很好的起點,因爲這會給您每秒大概30幀)。 – Nathan