C++入門使用向量

Question

井字棋樹中的所有posiible孩子都在那裏定大小的井字棋「板」 N返回所有給定板的孩子寫的實現。但是，它不會打印出每個矢量內的任何值，我不知道爲什麼。

這裏我們假設X（表示爲1）總是在O之前（表示爲-1）。空的空間是指爲0

這裏是實現文件，其中頭文件有vector<int> b_;和int n_;作爲其私有數據成員：

#include "tttboard.h" 
#include <vector> 
#include <iostream> 

using namespace std; 

tttboard::tttboard() 
{ 
} 

tttboard::tttboard(int n, vector<int> &e) 
{ 
    n_ = n; 
    for (int i=0; i<n*n; i++) 
    { 
     e.push_back(i); 
    } 
} 

tttboard::tttboard(int n){ 
    n_ = n; 
    for (int i=0; i<n*n; i++) 
     b_.push_back(0); 
} 

vector<tttboard> tttboard::possibleNextBoards(int turn) const{ 
    vector<tttboard> children; 
    int temp; 
    for (int i = 0; i < children.size(); i++) 
    { 
     children.push_back(temp); 
    } 
    return children; 
} 

bool tttboard::operator==(const tttboard& rhs) const 
{ 
    bool check = true; 
    for (int i=0; i < b_.size(); i++) 
    { 
     if (b_[i] == rhs.b_[i]) 
     { 
      continue; 
     } 
     else 
     { 
      check = false; 
      break; 
     } 
    } 
    return check; 
} 

ostream& operator << (ostream & output, const tttboard &board) 
{ 
    output << "{"; 
    for (int i=0; i < board.b_.size(); i++) 
    { 
     output << board.b_[i]; 
     if (i != board.b_.size() - 1) 
      output << ", "; 
    } 
    output << "}"; 
    return output; 
} 

編輯：這是主要的文件，我我有工作（道歉，如果這是一個有點長）

#include "tttboard.h" 
#include "gTree.h" 

#include <vector> 
#include <iostream> 
#include <algorithm> 

using namespace std; 

void Tokenize(string line, vector<string> & tokens, string delimiters = "\t "){ 
string token = ""; 
    string OneCharString = " "; 
    for (int i=0; i<line.size(); i++) 
      if (find(delimiters.begin(), delimiters.end(), line[i])!=delimiters.end()) // line[i] is one of the delimiter characters 
      { 
        if (token != "") 
          tokens.push_back(token); 
        token = ""; 
      } 
      else 
      { 
        OneCharString[0] = line[i]; 
        token +=OneCharString; 
      } 

    if (token != "") 
      tokens.push_back(token); 
} 

int getTurn(vector<int> b){ 
    int s = 0; 
    for (int i=0; i<b.size(); i++) 
     s+=b[i]; 
    if (s==0) 
     return 1; 
    else 
     return -1; 
} 

int main(int argc, char** argv){ 
    if (argc!=3){ 
     cout << "usage: executable.o n board\n example of board:(\"{0,0,1,0,0,-1,1,0,0}\")"; 
     return 1; 
    } 

int n= atoi(argv[1]); 
string str_board = argv[2]; 
vector<string> tokens; 
Tokenize(str_board,tokens," {,}"); 
vector<int> board; 
for (int i=0; i<tokens.size(); i++){ 
    board.push_back(atoi(tokens[i].c_str())); 
} 
if (n*n!= board.size()){ 
    cout<< "n and board are not consistent!\n"; 
    return 1; 
} 

    tttboard p(n,board); 
int turn = getTurn(board); 
vector<tttboard> v = p.possibleNextBoards(turn);  

cout <<"children of the given board:" << endl; 
for (int i=0; i<v.size(); i++) 
    cout << v[i] << endl; 

return 0; 

}

Answer 1

ST d :: cout被緩衝。如果添加一個std :: endl，輸出是否打印？嘗試在cout行之後添加std :: flush，例如cout < < .. < < std :: flush;