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我在數據庫中更新記錄有問題。 下面是錯誤的:Phalcon PresenceOf字段是必需的
Phalcon\Mvc\Model\Message Object
(
[_type:protected] => PresenceOf
[_message:protected] => field1 is required
[_field:protected] => private
[_model:protected] =>
[_code:protected] => 0
)
Phalcon\Mvc\Model\Message Object
(
[_type:protected] => PresenceOf
[_message:protected] => field2 is required
[_field:protected] => online
[_model:protected] =>
[_code:protected] => 0
)
這是數據庫模式:
CREATE TABLE `data`
(
`id` BINARY(16) NOT NULL,
`id_second` BINARY(16) NOT NULL,
`field1` TINYINT(1) NOT NULL DEFAULT 1,
`field2` TINYINT(1) NOT NULL DEFAULT 1,
`field3` INTEGER NOT NULL DEFAULT 0,
`name` VARCHAR(255) NOT NULL DEFAULT "",
PRIMARY KEY (`id`, `id_second`),
FOREIGN KEY (`id_second`) REFERENCES `data2` (`id`)
);
我可以創造新的紀錄,但我不能更新。 記錄發現後,我試圖取代價值和改變它:
$record->name = $save['name'];
$record->field1 = $save['field1'];
$record->field2 = $save['field2'];
$record->update();
但是,這顯示上面給出的錯誤。我不知道爲什麼,因爲當我顯示$record->field1
和$record->field2
時,它們不是null,而是true或false(這就是爲什麼它在數據庫中爲TINYINT
)。
模型中沒有驗證規則,並且id和id_second字段被設置屬性。
我試圖做到這一點這樣:
$result = Di::getDefault()->getModelsManager()->executeQuery('
UPDATE \Pulsar\Model\Data SET
name = :name:,
field1 = :field1:,
field2 = :field2:
WHERE
id = :id: AND id_second = :id_d2:
', [
'id' => $this->id,
'id_d2' => $this->id_second,
'name' => $this->name,
'field1' => $this->field1,
'field2' => $this->field2
], [
'id' => \PDO::PARAM_STR,
'id_d2' => \PDO::PARAM_STR,
'name' => \PDO::PARAM_STR,
'field1' => \PDO::PARAM_INT,
'field2' => \PDO::PARAM_INT
]
);
但結果是一樣的。 然而,這個工程:
$v1 = $record->field1 ? 1 : 0;
$v2 = $record->field2 ? 1 : 0;
$record->getReadConnection()->execute("
UPDATE data SET
name = '{$record->name}',
field1 = {$v1},
field2 = {$v2}
WHERE
id = '{$record->id}' AND id_second = '{$record->id_second}'
");
我怎樣才能實現與update()
或save()
功能一樣嗎?我提醒create()
和delete()
功能工作正常。