我強烈建議你不要使用字符串連接，因爲傑克遜提供了實現pojos的可行性。它乾淨，不易出錯。
首先聲明一個POJO的帳戶
public class Account {
private String id;
private String name;
private String email;
private String password;
public Account(String id, String name, String email, String password) {
this.id = id;
this.name = name;
this.email = email;
this.password = password;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
}
然後進行組織。請注意，我們這裏包括管理員帳戶
public class Organization {
private String id;
private String email;
private String name;
private String address;
private String zip;
private String city;
private String country;
private boolean enabled;
private int quota;
private String expires;
private List<Account> adminAccounts;
public Organization(String id, String email, String name, String address, String zip, String city, String country, boolean enabled, int quota, String expires, List<Account> adminAccounts) {
this.id = id;
this.email = email;
this.name = name;
this.address = address;
this.zip = zip;
this.city = city;
this.country = country;
this.enabled = enabled;
this.quota = quota;
this.expires = expires;
this.adminAccounts = adminAccounts;
}
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getAddress() {
return address;
}
public void setAddress(String address) {
this.address = address;
}
public String getZip() {
return zip;
}
public void setZip(String zip) {
this.zip = zip;
}
public String getCity() {
return city;
}
public void setCity(String city) {
this.city = city;
}
public String getCountry() {
return country;
}
public void setCountry(String country) {
this.country = country;
}
public boolean isEnabled() {
return enabled;
}
public void setEnabled(boolean enabled) {
this.enabled = enabled;
}
public int getQuota() {
return quota;
}
public void setQuota(int quota) {
this.quota = quota;
}
public String getExpires() {
return expires;
}
public void setExpires(String expires) {
this.expires = expires;
}
public List<Account> getAdminAccounts() {
return adminAccounts;
}
public void setAdminAccounts(List<Account> adminAccounts) {
this.adminAccounts = adminAccounts;
}
}
然後我們來實際的業務邏輯的名單。您可以創建任意數量的帳戶，你需要
Account account1 = new Account("1", "name1", "email1", "pass1");
Account account2 = new Account("2", "name2", "email2", "pass2");
，並將它們添加到列表
List<Account> accounts = new ArrayList<Account>();
accounts.add(account1);
accounts.add(account2);
然後將它們添加到本組織
Organization organization = new Organization("orgId", "orgEmail", "orgName", "orgAddress", "OrgZip", "orgCity", "orgCountry", true, 50, "2017-3-3", accounts);
基本上，你的String是通過賬戶代表和由組織代表的jsonBody。嘗試先創建這兩個帳戶pojos，並將它們組織並操作爲java對象
如何AdminAccount（或任何類的叫法）的等號/的hashCode實現？我注意到兩個帳戶都有一個空的ID。如果一個帳戶的平等是基於id的，那麼HashSet將（正確）忽略一個副本。 – yshavit
@yshavit它沒有在Account類中實現，我相信這也適用於「帳戶」設置，它已經（正確）有兩個元素 – grekier
啊，好點。 adminAccount中的一個元素是什麼樣的？它是否提供了關於發生了什麼的線索？ – yshavit