爲什麼我得到org.json.JSONException：類型java.lang.String的Value屬性不能轉換爲JSONObject？

Question

通過使用這個我得到的響應代碼，並試圖將字符串轉換爲JSONObject但得到異常。

public JSONObject getJSONFromUrl(String url,List<NameValuePair> nameValuePairsList) { 
     // Making HTTP request 
     try { 
      HttpParams param = new BasicHttpParams(); 
      HttpConnectionParams.setConnectionTimeout(param, 20000); 
      HttpConnectionParams.setSoTimeout(param, 20000); 
      DefaultHttpClient httpClient = new DefaultHttpClient(param); 
      HttpPost httpPost = new HttpPost(url); 
      httpPost.setHeader(HTTP.CONTENT_TYPE, "application/x-www-form-urlencoded"); 
      try { 
       httpPost.setEntity(new UrlEncodedFormEntity(nameValuePairsList)); 
      } catch (UnsupportedEncodingException e) { 
       e.printStackTrace(); 
      } 
      PropertyLogger.debug("URL Request: ", url.toString()); 
      PropertyLogger.debug("Encoded Params: ", nameValuePairsList.toString()); 
      HttpResponse httpResponse = httpClient.execute(httpPost); 
      int code = httpResponse.getStatusLine().getStatusCode(); 
      if (code != 200) { 
       PropertyLogger.debug("HTTP response code is:", Integer.toString(code)); 
       return null; 
      } else { 
       HttpEntity httpEntity = httpResponse.getEntity(); 
       is = httpEntity.getContent(); 
      } 
     } catch (ConnectTimeoutException e) { 
      // TODO: handle exception 
      PropertyLogger.error("Timeout Exception", e.toString()); 
      return null; 
     } catch (SocketTimeoutException e) { 
      // TODO: handle exception 
      PropertyLogger.error("Socket Time out", e.toString()); 
      return null; 
     } catch (UnsupportedEncodingException e) { 
      PropertyLogger.error("UnSupported Exception", e.toString()); 
      e.printStackTrace(); 
      return null; 
     } catch (ClientProtocolException e) { 
      e.printStackTrace(); 
      return null; 
     } catch (IOException e) { 
      e.printStackTrace(); 
      return null; 
     } 
     String TAG = "PropertyJsonParser"; 
     try { 
      BufferedReader reader = new BufferedReader(new InputStreamReader(is, "iso-8859-1"), 8); 
      StringBuilder sb = new StringBuilder(); 
      String line = null; 
      while ((line = reader.readLine()) != null) 
      { 
       sb.append(line + "\n"); 
      } 
      is.close(); 
      jsonResp = sb.toString(); 
      PropertyLogger.debug("Content: ", sb.toString()); 
     } catch (Exception e) { 
      PropertyLogger.error("Buffer Error", "Error converting Response " + e.toString()); 
      return null; 
     } 
     // try parse the string to a JSON object 
     try { 
      jObj = new JSONObject(jsonResp); 
     } catch (JSONException e) { 
      PropertyLogger.error("JSON Parser", "Error parsing data :" + e.toString()); 
      return null; 
     } 

     return jObj; 
    } 

Answer 1

你，因爲你沒有接受適當的JSON響應得到這個錯誤。

檢查您的API響應，並可能還提供您的API響應。

Answer 2

因爲你的變量jsonResp包含字符串值不的JSONObject因此請首先打印，並確保它是字符串類型值與否。