我想更新，但它是增加一個新的行

Question

這是我更新的代碼： PS：EMPID是一個外鍵，但我認爲不應該是理性和代碼在CakePHP的

if($this->request->is('post')) 
     { 
      $this->request->data["Leave"]["empid"] = $this->request->data["id"]; 
      $this->Leave->empid = $this->request->data["Leave"]["empid"]; 
      $this->request->data["Leave"]["leave_start"] = $this->request->data["start_date"]; 
      $this->request->data["Leave"]["leave_end"] = $this->request->data["end_date"]; 
      $this->request->data["Leave"]["leave_taken"] = $this->request->data["leave_taken"]; 

      if($this->Leave->save($this->request->data['Leave'])) 
      { 
       return $this->redirect(array('action' => 'manage_leave')); 
      } 
     } 

//此代碼插入新行而不是更新，也不會在新行中添加任何值

Answer 1

可能是您試圖使用simple save來更新外部表數據。外鍵

Model::updateAll(array $fields, mixed $conditions) 

更新多條記錄例

$this->Ticket->updateAll(
    array('Ticket.status' => "'closed'"), 
    array('Ticket.customer_id' => 453) 
); 

簡單節省的主鍵

確保您的HTML有empid

echo $this->Form->input('Leave.empid', array('type' => 'hidden')); 

保存模型

$this->Leave->empid = $this->request->data["Leave"]["empid"]; //2 
$this->Leave->save($this->request->data); 

在這兩者之間，你也可以嘗試set模型數據，並檢查$this->Leave->validates()和$this->Leave->validationError如果他們給任何驗證錯誤。

// Create: id isn't set or is null 
$this->Recipe->create(); 
$this->Recipe->save($this->request->data); 

// Update: id is set to a numerical value 
$this->Recipe->id = 2; 
$this->Recipe->save($this->request->data); 

你可以找到所有Saving your data

希望更多的信息，這可以幫助你:)

Answer 2

而且萬一要是$ EMPID是離開模型的相應表的主鍵（如葉），只是更換：

$this->Leave->empid = $this->request->data["Leave"]["empid"]; 

通過

$this->Leave->id = $this->request->data["Leave"]["empid"];