無法訪問返回對象的屬性？

//SomeObject.h 
#import <Foundation/Foundation.h> 


@interface SomeObject : NSObject { 

} 
@property NSInteger aProperty; 
@end 

//main.m 

#import <Foundation/Foundation.h> 
#import "SomeObject.h" 

int main (int argc, const char * argv[]) 
{ 

    NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init]; 

    NSMutableDictionary *dictionary = [[NSMutableDictionary alloc] init]; 
    [dictionary setObject:[[[SomeObject alloc] init] autorelease] forKey:@"key1"]; 
    [dictionary setObject:[[[SomeObject alloc] init] autorelease] forKey:@"key2"]; 
    [dictionary objectForKey:@"key1"].aProperty = 5; //Error HERE 
    [dictionary release]; 

    [pool drain]; 
    return 0; 
}

但在該行的XCode給我這些錯誤：無法訪問返回對象的屬性？

error: Semantic Issue: Member reference type 'struct objc_object *' is a pointer; maybe you meant to use '->'? 
error: Semantic Issue: No member named 'aProperty' in 'struct objc_object'

我不能訪問返回的對象的屬性？（我的意思是，沒有直接調用setter方法）

來源

2011-08-29 Michele De Pascalis

煤焦與指針「*」？我是noob，但我從來沒有看到帶有星號的字符，就像你做的那樣「char * argv []」 – doNotCheckMyBlog

這就像編寫char argv [] []或char ** argv ...這是一個二元數組，每個標準C main接收命令行參數應該有這樣的參數列表。 –

你需要將返回的對象：

((SomeObject*)[dictionary objectForKey:@"key1"]).aProperty = 5;

或：

[(SomeObject*)[dictionary objectForKey:@"key1"] setAProperty: 5];

或：

SomeObject* obj = [dictionary objectForKey:@"key1"]; 
obj.aProperty = 5;

來源

2011-08-29 10:34:43 Felix

仍然認爲我不必在C++中做到這一點......謝謝！ –

稍等片刻，解決方案1應該是'（（SomeObject *）[dictionary objectForKey：@「key1」]）。aProperty = 5;' –

沒關係，只是改正了它 – Felix

無法訪問返回對象的屬性？

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