爲什麼多個數據不插入此代碼

Question

我有一個tbl_employee表和tbl_time表，我想插入多個數據插入考勤，但是當我點擊提交按鈕它只插入單個數據。但問題出在哪裏，幫我找出this..this是插入代碼

require './db_connect.php'; 
class Time extends Db_connect { 

    protected $link; 

    public function __construct() { 
     $this->link = $this->database_connection(); 
    } 

    public function attendance_insert($data) { 
     extract($data); 
     $cur_date = date('Y-m-d'); 

     foreach ($time_attendance as $attn_key => $attn_value) { 
      if ($attn_value == 'P') { 
       $SQL = "INSERT INTO tbl_time(employee_id,time_date,time_attendance)VALUES('$attn_key','$cur_date','P')"; 
       $atten_date=mysqli_query($this->link, $SQL); 
      } else if ($attn_value == 'A') { 
       $SQL = "INSERT INTO tbl_time(employee_id,time_date,time_attendance)VALUES('$attn_key','$cur_date','A')"; 
       $atten_date=mysqli_query($this->link, $SQL); 

      } 
      if ($atten_date) { 
       $massage = "<div class='alert alert-success text-center'><h5>Attendance insert successfully</h5></div>"; 
       return $massage; 
      } else { 
       die('Attendance insert query problem' . mysqli_error($this->link)); 
      } 
     } 
    } 
} 

這是HTML代碼

<?php 

    require_once './time.php'; 
    $obj_time = new Time() 
    $massage = ''; 
    if (isset($_POST['btn'])) { 
     $massage = $obj_time->attendance_insert($_POST); 
    } 

    $employee_view = $obj_employee->employee_all_view(); 
    ?> 
    <div class="container-fluid"> 
     <div class="row"> 
      <center> 
       <a href="time.php" class="btn btn-sm btn-default glyphicon glyphicon-backward pull-left" id="show_form"></a> 
       <span style="font-size:1.8em;">Attendance form</span> 
      </center> 
     </div> 
    </div> 
    <hr/> 


    <?php echo $massage; ?> 
    <div class="container-fluid"> 
     <div class="row"> 
      <div class="col-lg-12"> 

       <div class="panel panel-body panel-default"> 
        <div class="well text-center" style="font-size:15px;"> 
         <strong>Date :</strong> 
         <?php $current_date = date('Y-M-d'); 
         echo $current_date; ?> 
        </div> 
        <form class="form-horizontal" method="post"> 
         <table class="table table-striped table-responsive text-center"> 
          <tr> 
           <td><b>Serial</b></td> 
           <td><b>Name</b></td> 
           <td><b>ID</b></td> 
           <td><b>Attendance</b></td> 
          </tr> 
          <?php 
          $i = 0; 
          while ($employee_info = mysqli_fetch_assoc($employee_view)) { 
           extract($employee_info); 
           $i++; 
           ?> 
           <tr> 
            <td><?php echo $i; ?></td> 
            <td><?php echo $employee_first_name . ' ' . $employee_last_name; ?></td> 
            <td><?php echo $employee_id; ?></td> 
            <td> 
             <input type="radio" name="time_attendance[<?php echo $employee_id; ?>]" value="P">P &nbsp; 
             <input type="radio" name="time_attendance[<?php echo $employee_id; ?>]" value="A">A 
            </td> 
           </tr> 
          <?php } ?> 

          <tr> 
           <td colspan="4"> 
            <input type="submit" class="btn btn-primary btn-block" name="btn" value="submit"/> 
           </td> 
          </tr> 

         </table> 
        </form> 
       </div> 
      </div> 
     </div> 
    </div> 

Answer 1

此：

foreach($time_attendance as $attn_key => $attn_value){ 
    $SQL = "INSERT INTO tbl_time(employee_id,time_date,time_attendance) 
     VALUES('$attn_key','$cur_date','A')"; 
    $atten_date = mysqli_query($this->link, $SQL); 

    if ($atten_date) { 
     $massage = "<div class=''><h5>Attendance insert successfully</h5></div>"; 
     return $massage; 
    } 
} 

字面上要求打破與return $massage; foreach，如果你查詢成功......所以是的，你只會有一個記錄。

把你的回報放在foreach之外。