斯威夫特：重用代碼傳遞類參數

Question

我想重用代碼，所以我創建redirectToTabBarControllerChild

func redirectToTabBarControllerChild(storyboardName: String, tabBarIndex: Int, segueID: String, viewController: UITableViewController) { 
    let storyboardMain = UIStoryboard(name: storyboardName, bundle: nil) 
    let tabBarController = storyboardMain.instantiateViewController(withIdentifier: "TabBarController") as! UITabBarController 
    window?.rootViewController = tabBarController 
    tabBarController.selectedIndex = tabBarIndex 
    let navigationViewContrller = tabBarController.childViewControllers[tabBarIndex] as! UINavigationController 
    let currentViewContrller = navigationViewContrller.childViewControllers.first as! viewController 
    currentViewContrller.performSegue(withIdentifier: segueID, sender: nil) 
    window?.makeKeyAndVisible() 
} 

最後一個參數，我想傳遞ProfileViewController例如。但我有一個錯誤在這行：let currentViewContrller = navigationViewContrller.childViewControllers.first as! viewController

Use of undeclared type viewController

有誰知道我怎麼能做到這一點？

Answer 1

的navigationController?.childViewControllers是UIViewControllers一個array。你獲得first屬性，這意味着你需要將它投射到as! UIViewController，這將強制施放它，它不會是一個可選項。

你想要做的是將其轉換爲UITableViewController，所以像這樣做：

if let vc = navigationViewContrller.childViewControllers.first as? UITableViewController { 
    // Will succeed if the first is of type UITableViewController 
    // Use vc in here 
} 

Answer 2

替換的viewController到的UITableViewController