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我有一個小問題。 我已經寫了這段代碼將值添加到mysql數據庫,但是當我運行代碼,並且出現錯誤時。有誰能夠幫助我?Php mysqli-> real_escape_string和MYSQL
的代碼:
$fel = $mysqli->query("INSERT INTO deleted (uid,buy_type,prop_type,district,street,room_min,room_max,price_min,price_max,condition_type,heat_type,lift_type,parking_type,type_of_del,when)
VALUES ('".$mysqli->real_escape_string($letomb['uid'])."',
'".$mysqli->real_escape_string($letomb['buy_type'])."',
'".$mysqli->real_escape_string($letomb['prop_type'])."',
'".$mysqli->real_escape_string($letomb['district'])."',
'".$mysqli->real_escape_string($letomb['street'])."',
'".$mysqli->real_escape_string($letomb['room_min'])."',
'".$mysqli->real_escape_string($letomb['room_max'])."',
'".$mysqli->real_escape_string($letomb['price_min'])."',
'".$mysqli->real_escape_string($letomb['price_max'])."',
'".$mysqli->real_escape_string($letomb['condition_type'])."',
'".$mysqli->real_escape_string($letomb['heat_type'])."',
'".$mysqli->real_escape_string($letomb['lift_type'])."',
'".$mysqli->real_escape_string($letomb['parking_type']).",
'".$mysqli->real_escape_string($type_of_del)."',
now())") or die($mysqli->error);
錯誤:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'when) VALUES ('3', 'kiado', 'lakas', '1'' at line 1
好吧我已經糾正了這個問題,並且我去了那個錯誤: –