陣列到字符串轉換（不能讓它工作）

Question

好的我想拉一個特定的數據行對應於我的網頁上登錄的用戶名我已經開始我的會話，但由於某種原因，我不能得到代碼工作。我不斷收到一個「數組到字符串轉換」的行WHERE用戶名='$ _SESSION [用戶]'「）;」我做錯了什麼？如果我設置用戶名=我需要它來從會話ID會畫畫，所以它會根據登錄衛生組織顯示不同的值。

<?php 


require("common.php"); 


if(empty($_SESSION['user'])) 
{ 

    header("Location: login.php"); 


    die("Redirecting to login.php"); 
} 


?> 





<?php 

$con=mysqli_connect("localhost","root","nathan","site"); 
// Check connection 
if (mysqli_connect_errno()) 
{ 
echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
} 

$result = mysqli_query($con,"SELECT * FROM users 
WHERE username = '".$_SESSION['user']."'"); 

while($row = mysqli_fetch_array($result)) 
{ 
echo $row['username'] . " " . $row['att']; 
echo "<br>"; 
} 
?> 

here are my other corresponding files 

<?php 


$username = "root"; 
$password = "nathan"; 
$host = "localhost"; 
$dbname = "site"; 




$options = array(PDO::MYSQL_ATTR_INIT_COMMAND => 'SET NAMES utf8'); 


try 
{ 


$db = new PDO("mysql:host={$host};dbname={$dbname};charset=utf8",                        $username,      $password,    $options); 
} 
catch(PDOException $ex) 
{ 

    die("Failed to connect to the database: " . $ex->getMessage()); 
} 


$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 


$db->setAttribute(PDO::ATTR_DEFAULT_FETCH_MODE, PDO::FETCH_ASSOC); 


if(function_exists('get_magic_quotes_gpc') && get_magic_quotes_gpc()) 
{ 
    function undo_magic_quotes_gpc(&$array) 
    { 
     foreach($array as &$value) 
     { 
      if(is_array($value)) 
      { 
       undo_magic_quotes_gpc($value); 
      } 
      else 
      { 
       $value = stripslashes($value); 
      } 
     } 
    } 

    undo_magic_quotes_gpc($_POST); 
    undo_magic_quotes_gpc($_GET); 
    undo_magic_quotes_gpc($_COOKIE); 
} 


header('Content-Type: text/html; charset=utf-8'); 


session_start(); 

和我的login文件

<?php 


require("common.php"); 


$submitted_username = ''; 



if(!empty($_POST)) 
{ 

    $query = " 
     SELECT 
      id, 
      username, 
      password, 
      salt, 
      email 
     FROM users 
     WHERE 
      username = :username 
    "; 


    $query_params = array( 
     ':username' => $_POST['username'] 
    ); 

    try 
    { 

     $stmt = $db->prepare($query); 
     $result = $stmt->execute($query_params); 
    } 
    catch(PDOException $ex) 
    { 

     die("Failed to run query: " . $ex->getMessage()); 
    } 


    $login_ok = false; 


    $row = $stmt->fetch(); 
    if($row) 
    { 

     $check_password = hash('sha256', $_POST['password'] . $row['salt']); 
     for($round = 0; $round < 65536; $round++) 
     { 
      $check_password = hash('sha256', $check_password . $row['salt']); 
     } 

     if($check_password === $row['password']) 
     { 

      $login_ok = true; 
     } 
    } 


    if($login_ok) 
    { 

     unset($row['salt']); 
     unset($row['password']); 


     $_SESSION['user'] = $row; 


     header("Location: private.php"); 
     die("Redirecting to: private.php"); 
    } 
    else 
    { 

     print("Login Failed."); 


     $submitted_username = htmlentities($_POST['username'], ENT_QUOTES, 'UTF-8'); 
    } 
} 

?> 
<h1>Login</h1> 
<form action="login.php" method="post"> 
Username:<br /> 
<input type="text" name="username" value="<?php echo $submitted_username; ?>" /> 
<br /><br /> 
Password:<br /> 
<input type="password" name="password" value="" /> 
<br /><br /> 
<input type="submit" value="Login" /> 
</form> 
<a href="register.php">Register</a> 

Answer 1

也許這會工作？

<?php 
session_start(); 
$con=mysqli_connect("localhost","root","xxx","xxxx"); 
// Check connection 
if (mysqli_connect_errno()) 
{ 
echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
} 

$result = mysqli_query($con,"SELECT * FROM users 
WHERE username = '".$_SESSION['user']."'"); 

while($row = mysqli_fetch_array($result)) 
{ 
echo $row['username'] . " " . $row['att']; 
echo "<br>"; 
} 
?> 

Answer 2

您收到此錯誤的原因很簡單。是你的$_SESSION['user'];是逸岸數組..此錯誤消息的一個簡單的例子：

$Array = array (1,2,3,4,5); 
echo $Array; 

這就是你的錯誤..

所以我沒有看到實際的$_SESSION變量..建議是執行：

echo "<pre>"; 
print_r($_SESSION); 
echo "</pre>"; 

這將顯示你的整個會話數組，並會告訴你我告訴你什麼。

---

隨着你說了什麼。

$Username_Values = $_SESSION['user']; 
$Username_Values['username']; // Will output the user name