MySQL查詢錯誤，試圖連接表

Question

任何人都可以看到爲什麼這段代碼返回錯誤？

"SELECT 
a.widget_id, 
c.additional_widget_id 
FROM 
exp_widgets AS a, 
INNER JOIN exp_widget_additional AS c ON a.entry_id = c.additional_entry_id 
WHERE 
a.template = 3 
AND 
c.additional_template_id = 3 
AND 
(a.entry_id = 6 OR c.additional_entry_id = 6) 
"; 

任何幫助表示讚賞。

Answer 1

你有一個流氓逗號：

... 
exp_widgets AS a, 
INNER JOIN exp_widget_additional` 
... 

應該

... 
exp_widgets AS a 
INNER JOIN exp_widget_additional 
...