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任何人都可以看到爲什麼這段代碼返回錯誤?MySQL查詢錯誤,試圖連接表
"SELECT
a.widget_id,
c.additional_widget_id
FROM
exp_widgets AS a,
INNER JOIN exp_widget_additional AS c ON a.entry_id = c.additional_entry_id
WHERE
a.template = 3
AND
c.additional_template_id = 3
AND
(a.entry_id = 6 OR c.additional_entry_id = 6)
";
任何幫助表示讚賞。
和錯誤會??? – 2010-04-07 17:52:00
如果你添加MySQL給你的錯誤會有幫助。 – jemfinch 2010-04-07 17:52:47
如果您發佈錯誤消息,它可能會有所幫助。 – 2010-04-07 17:52:57