自定義路由元素不能在cakephp中工作

我正在使用CakePHP 2.1。事情是這樣的......自定義路由元素不能在cakephp中工作

我想在這個格式的URL：

http://mysite.com/[username]/

哪裏[username]可以是動態的，並呼籲已經實施的「用戶」控制器。

下面是routes.php文件中定義的路徑：

Router::connect(
    '/:username', 
    array('controller' => 'users', 'action' => 'profile'), 
    array(
     'pass' => array('username'), 
     'username' => '[a-zA-Z0-9][/-_.]+' 
    ));

如果我試圖達到http://mysite.com/testuser顯示此錯誤：

"Missing Controller 
Error: testuserController could not be found."

這裏是我的整個routes.php文件文件：

<?php 
/** 
* Routes configuration 
* 
* In this file, you set up routes to your controllers and their actions. 
* Routes are very important mechanism that allows you to freely connect 
* different urls to chosen controllers and their actions (functions). 
* 
* PHP 5 
* 
* CakePHP(tm) : Rapid Development Framework (http://cakephp.org) 
* Copyright 2005-2012, Cake Software Foundation, Inc. (http://cakefoundation.org) 
* 
* Licensed under The MIT License 
* Redistributions of files must retain the above copyright notice. 
* 
* @copyright  Copyright 2005-2012, Cake Software Foundation, Inc. (http://cakefoundation.org) 
* @link   http://cakephp.org CakePHP(tm) Project 
* @package  app.Config 
* @since   CakePHP(tm) v 0.2.9 
* @license  MIT License (http://www.opensource.org/licenses/mit-license.php) 
*/ 

    Router::connect('/', array('controller' => 'home', 'action' => 'index')); 

    Router::connect(
    '/:username', 
    array('controller' => 'users', 'action' => 'profile'), 
    array(
     'pass' => array('username'), 
     'username' => '[a-zA-Z0-9][/-_.]+' 
    )); 

/** 
* Load all plugin routes. See the CakePlugin documentation on 
* how to customize the loading of plugin routes. 
*/ 
    CakePlugin::routes(); 

/** 
* Load the CakePHP default routes. Remove this if you do not want to use 
* the built-in default routes. 
*/ 
    require CAKE . 'Config' . DS . 'routes.php';

我試過這樣的事情：

Router::connect(
    '/users/:username', 
    array('controller' => 'users', 'action' => 'profile'), 
    array(
     'pass' => array('username'), 
     'username' => '[a-zA-Z0-9][/-_.]+' 
    ));

和這種方式它工作...！然後我可以得到︰$ this-> request-> params ['pass'] [0]

所以，現在這是一個問題：爲什麼它不能在路徑的第一級（域。 COM /：暱稱）？

來源

2012-04-12 Line

的用戶名能否請您發表您的完整路徑文件？ – Joep 2012-04-12 14:19:15

@Joep它在那裏:) – Line 2012-04-12 14:30:13

我不確定你需要在那裏有'：username'，因爲它的參數不是'：controller'或'：action'可能需要檢查手冊，http：// book.cakephp.org/2.0/en/development/routing.html#routes-configuration – 2012-04-12 16:32:17

嘗試：

Router::connect('/*', array('controller' => 'users', 'action' => 'actionName'));

，然後在UsersController如果你有

public function foo($username){ 
    ... 
}

$用戶名包含在URL

來源

2012-06-03 23:59:55 chrisbulmer

自定義路由元素不能在cakephp中工作

回答

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