xslt 2.0按編​​號排序元素

Question

我有以下輸入XML， 出於某種原因，我的xslt無法對其進行排序。 請指教。 感謝您的見解。 這是完整的XML ............................................ ...........

我想根據D_628字段對G_SHL段的內容進行排序。

`<?xml version="1.0" encoding="UTF-8"?> 
<LIST> 
    <S_ISA> 
     <D_I01>00</D_I01> 
     <D_I02/> 
     <D_I03>00</D_I03> 
     <D_I04/> 
     <D_I05>01</D_I05> 
     <D_I06></D_I06> 
     <D_I05_2>ZZ</D_I05_2> 
     <D_I07></D_I07> 
     <D_I08>160427</D_I08> 
     <D_I09>1106</D_I09> 
     <D_I10>U</D_I10> 
     <D_I11>00401</D_I11> 
     <D_I12>000000001</D_I12> 
     <D_I13>0</D_I13> 
     <D_I14/> 
     <D_I15>&gt;</D_I15> 
     <S_GS> 
      <D_479>SH</D_479> 
      <D_142></D_142> 
      <D_124></D_124> 
      <D_373>20160427</D_373> 
      <D_337>1106</D_337> 
      <D_28>1</D_28> 
      <D_455>X</D_455> 
      <D_480>004010</D_480> 
      <S_ST> 
       <D_143>856</D_143> 
       <D_329>0001</D_329> 
       <S_BSN> 
        <D_353>00</D_353> 
        <D_396>0081664420</D_396> 
        <D_373>20160426</D_373> 
        <D_337>1347</D_337> 
        <D_1005>0001</D_1005> 
       </S_BSN> 
       <G_SHL> 
        <S_HL> 
         <D_628>0000001</D_628> 
         <D_734>0000000</D_734> 
         <D_735>S</D_735> 
         <S_PRF> 
          <D_324>SITT10-1447195769627</D_324> 
          <D_328>SITT10-1447195769627</D_328> 
         </S_PRF> 
         <S_MEA> 
          <D_737>PD</D_737> 
          <D_738>G</D_738> 
          <D_739>0.081</D_739> 
          <C_C001> 
           <D_355>KG</D_355> 
          </C_C001> 
         </S_MEA> 
         <S_TD1> 
          <D_103>PKG</D_103> 
          <D_80>00002</D_80> 
          <D_187>G</D_187> 
          <D_81>00000.18</D_81> 
          <D_355>LB</D_355> 
         </S_TD1> 
         <S_TD5> 
          <D_133>O</D_133> 
          <D_66>2</D_66> 
          <D_368>CC</D_368> 
         </S_TD5> 
         <S_REF> 
          <D_128>WH</D_128> 
          <D_127>WH:</D_127> 
         </S_REF> 
         <S_REF> 
          <D_128>RN</D_128> 
          <D_127>RN:</D_127> 
         </S_REF> 
         <S_DTM> 
          <D_374>011</D_374> 
          <D_373>20160414</D_373> 
         </S_DTM> 
         <G_SN1> 
          <S_N1> 
           <D_98>ST</D_98> 
           <D_93>C3333</D_93> 
           <S_N3> 
            <D_166>TEST</D_166> 
           </S_N3> 
           <S_N4> 
            <D_19>TEST</D_19> 
            <D_116>12345</D_116> 
            <D_26>US</D_26> 
           </S_N4> 
          </S_N1> 
         </G_SN1> 
        </S_HL> 
       </G_SHL> 
       <G_SHL> 
        <S_HL> 
         <D_628>0000002</D_628> 
         <D_734>0000001</D_734> 
         <D_735>O</D_735> 
         <S_MAN> 
          <D_88>CP</D_88> 
          <D_87></D_87> 
         </S_MAN> 
        </S_HL> 
       </G_SHL> 
       <G_SHL> 
        <S_HL> 
         <D_628>0000003</D_628> 
         <D_734>0000002</D_734> 
         <D_735>P</D_735> 
        </S_HL> 
       </G_SHL> 
       <G_SHL> 
        <S_HL> 
         <D_628>0000005</D_628> 
         <D_734>0000002</D_734> 
         <D_735>P</D_735> 
        </S_HL> 
       </G_SHL> 
       <G_SHL> 
        <S_HL> 
         <D_628>0000004</D_628> 
         <D_734>0000003</D_734> 
         <D_735>I</D_735> 
         <S_LIN> 
          <D_350>000010</D_350> 
          <D_235>SK</D_235> 
          <D_234></D_234> 
          <D_235_2>BP</D_235_2> 
          <D_234_2></D_234_2> 
         </S_LIN> 
         <S_SN1> 
          <D_350></D_350> 
          <D_382>2.000</D_382> 
          <D_355>EA</D_355> 
          <D_668>AC</D_668> 
         </S_SN1> 
        </S_HL> 
       </G_SHL> 
       <G_SHL> 
        <S_HL> 
         <D_628>0000006</D_628> 
         <D_734>0000005</D_734> 
         <D_735>I</D_735> 
         <S_LIN> 
          <D_350>000020</D_350> 
          <D_235></D_235> 
          <D_234></D_234> 
          <D_235_2>BP</D_235_2> 
          <D_234_2></D_234_2> 
         </S_LIN> 
         <S_SN1> 
          <D_382>1.000</D_382> 
          <D_355>EA</D_355> 
          <D_668>AC</D_668> 
         </S_SN1> 
        </S_HL> 
       </G_SHL> 
       <S_CTT> 
        <D_354>1</D_354> 
       </S_CTT> 
       <S_SE> 
        <D_96>[]</D_96> 
        <D_329>0001</D_329> 
       </S_SE> 
      </S_ST> 
      <S_GE> 
       <D_97>0</D_97> 
       <D_28>1</D_28> 
      </S_GE> 
     </S_GS> 
     <S_IEA> 
      <D_I16>01</D_I16> 
      <D_I12>000000001</D_I12> 
     </S_IEA> 
    </S_ISA> 
</LIST>` 

Answer 1

嘗試

<xsl:template match="@*|node()"> 
    <xsl:copy> 
     <xsl:apply-templates select="@*|node()"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="/LIST/S_ISA/S_GS/S_ST"> 
    <xsl:copy> 
    <xsl:apply-templates select="@*"/> 
    <xsl:apply-templates select="G_SHL"> 
     <xsl:sort select="S_HL/D_628" data-type="number" order="descending"/> 
    </xsl:apply-templates> 
    </xsl:copy> 
</xsl:template> 

我無法驗證路徑/LIST/S_ISA/S_GS/S_ST但假設你有你的真實XML的祖先元素。

如果有可能，你想保持在原來的輸入位置，其中一個方法在XSLT 2.0同級元素是先確定要排序與for-each-group group-adjacent相鄰元素：

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:xs="http://www.w3.org/2001/XMLSchema" 
    exclude-result-prefixes="xs" 
    version="2.0"> 

    <xsl:output indent="yes"/> 
    <xsl:strip-space elements="*"/> 

    <xsl:template match="@*|node()"> 
     <xsl:copy> 
      <xsl:apply-templates select="@*|node()"/> 
     </xsl:copy> 
    </xsl:template> 

    <xsl:template match="/LIST/S_ISA/S_GS/S_ST"> 
     <xsl:copy> 
      <xsl:apply-templates select="@*"/> 
      <xsl:for-each-group select="*" group-adjacent="boolean(self::G_SHL)"> 
       <xsl:choose> 
        <xsl:when test="current-grouping-key()"> 
         <xsl:apply-templates select="current-group()"> 
          <xsl:sort select="S_HL/D_628" data-type="number" order="descending"/> 
         </xsl:apply-templates> 
        </xsl:when> 
        <xsl:otherwise> 
         <xsl:apply-templates select="current-group()"></xsl:apply-templates> 
        </xsl:otherwise> 
       </xsl:choose> 
      </xsl:for-each-group> 
     </xsl:copy> 
    </xsl:template> 

</xsl:stylesheet>