如何使用空白

punc_list = [".",";",":","!","?","/","\\",",","#","@","$","&",")","(","'","\""] 
new_s = '' 
for i in s: 
    if i not in punc_list: 
     new_s += i 
return new_s.lower()

更換標點符號如果輸入如何使用空白

s = ("Hey! M'y nam;e i's")

我想輸出是：

s = ('hey m y name e i s')

我無法用空格代替PUNC

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2017-03-05 Mar

這個功課，還是可以使用正則表達式？另外，只是_exactly那些標點符號或_all_特殊字符？ –

在'else'分支中，添加一個空白區域。 – DyZ

@tobias_k是的，它是作業。我正在考慮所有特殊字符 – Mar

像@DYZ說，你只需要在另一個條件語句用空格代替特殊字符：

def func(s): 
    punc_list = [".",";",":","!","?","/","\\",",","#","@","$","&",")","(","'","\""] 
    new_s = '' 
    for i in s: 
     if i not in punc_list: 
      new_s += i 
     else: 
      new_s += ' ' 
    return new_s.lower() 

s = ("Hey! M'y nam;e i's") 
new_s = func(s) 
print (new_s)

輸出看起來像你想要的東西：hey m y nam e i s

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2017-03-05 21:56:27 user3813674

我只需在if i not in punc_list:中添加else語句，以便代碼如下所示：

punc_list = [".",";",":","!","?","/","\\",",","#","@","$","&",")","(","'","\""] 
new_s = '' 
for i in s: 
    if i not in punc_list: 
     new_s += i 
    else: 
     new_s += ' ' 

return new_s.lower()

這樣做只是說：如果字符不在標點符號列表將其添加到新string。如果它位於標點符號列表中，請將空格添加到新的string。

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2017-03-05 21:55:35

使用str.translate。將punc_list中的所有字符轉換爲空格。

>>> punc_list = [".",";",":","!","?","/","\\",",","#","@","$","&",")","(","'","\""] 
>>> s = "Hey! M'y nam;e i's" 
>>> s.translate({ord(p): " " for p in punc_list}) 
'Hey M y nam e i s'

您可以創建使用字典理解的蒼蠅，它映射所有的標點字符代碼字典映射（使用ord功能）的空間。

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2017-03-05 21:58:05

爲什麼不只是'{ord（x）：''爲punc_list中的x}'？ –

是更簡單的謝謝 –

看到這個代碼，使用2個循環：

punc_list = [".",";",":","!","?","/","\\",",","#","@","$","&",")","(","'","\""] 
s = "Hey! M'y nam;e i's" 
new_s = '' 

for x in punc_list: 
    for i in s: 
    if i==x: 
     s=s.replace(i,new_s) 


print(s)

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2017-03-05 21:58:26

你忘了添加一個空格' '當字符是標點符號。另外，punc_list實際上不一定是list;您可以將其設爲一個長字符串並迭代字符，或者如註釋中所述，只需使用string.punctuation即可。並提高查找速度，你也可以讓它set，但它確實不應該多大關係在這種情況下：

punc_list = set('.;:!?/\\,#@$&)(\'"') # or use string.punctuation 

def no_punc(s): 
    new_s = '' 
    for i in s: 
     if i not in punc_list: 
      new_s += i 
     else: 
      new_s += ' ' 
    return new_s.lower()

還是有點短，使用三元表達式... if ... else ...：

def no_punc(s): 
    new_s = '' 
    for i in s: 
     new_s += i if i not in punc_list else ' ' 
    return new_s.lower()

或者更短，使用str.join：

def no_punc(s): 
    return ''.join(i if i not in punc_list else ' ' for i in s).lower()

或甚至短，基於R egular expressions re：

import re 
def no_punc(s): 
    return re.sub("\W", " ", s).lower()

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2017-03-05 21:58:26

作業問題是否應該幫助您瞭解循環？學習字典和翻譯也是有用的，我想。

t = str.maketrans(dict.fromkeys(punc_list, " ")) 
new_s = s.lower().translate(t)

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2017-03-05 22:02:46

如何使用空白

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