python試試格式除外

Question

try: 
    num = int(input("Give me an integer between 1 and 100:")) 
    while num > 100 or num < 1: 
     print ("Sorry, that is not an integer between 1 and 100. Try again.") 
     num = int(input("Give me an integer between 1 and 100:")) 
except: 
    print ("Sorry, that is not an integer between 1 and 100. Try again.") 
else: 
    print ("Thank you for your input") 

如何告訴Python如果輸入了諸如「pear」或「sd23214」之類的輸入，還打印出「sorry try again」？謝謝。

Answer 1

只是包裝這一切在while循環

while True: 
    try: 
     num = int(input("Give me an integer between 1 and 100:")) 
     if num > 100 or num < 1: 
      print ("Sorry, that is not an integer between 1 and 100. Try again.") 
      continue 
    except ValueError: 
     print ("Sorry, that is not an integer between 1 and 100. Try again.") 
    else: 
     print ("Thank you for your input") 
     break 

大多數人可能不會使用這裏的else條款

while True: 
    try: 
     num = int(input("Give me an integer between 1 and 100:")) 
     if num > 100 or num < 1: 
      raise ValueError 
     print ("Thank you for your input") 
     break 
    except ValueError: 
     print ("Sorry, that is not an integer between 1 and 100. Try again.") 

Answer 2

這是做一個更好/更簡單的方法（在我看來）：

while True: 
    try: 
     num = int(input("Enter an integer between 1 and 100: ")) 
     if type(num) != int or num not in range(1, 101): #second argument is exclusive 
      raise ValueError 
     else: 
      print("Thank you.") 
      break 
    except ValueError: 
     print("Input must be an integer within 1 and 100. Try again.") 

使用range是一個很好的w唉，這樣做，而不是使用if num > 101 or num < 1。