如何從JAX-RS獲取原始請求的URI javax.ws.rs.core.Response

Question

我正在嘗試爲JAX-RS編寫一個定製的ExceptionMapper類。我想以某種方式讀取來自JAX-RS javax.ws.rs.core.Response對象的原始請求URI。

當我檢查與在調試模式下的IntelliJ IDEA響應對象然後我可以看到下面的路徑下此信息：響應>上下文> resolvedUri其中
類型context的是org.glassfish.jersy.client.ClientResponse。這個類有一個resolvedUri變量，它擁有我需要的信息。

我能以某種方式獲得這些信息嗎？我如何寫我的getRequestUri(response)方法？

public class MyExceptionMapper implements ExceptionMapper<WebApplicationException> { 

    @Override 
    public Response toResponse(WebApplicationException error) { 

     Response response = error.getResponse(); 
     ErrorResponse errorResponse = ErrorResponseBuilder 
       .builder() 
       .httpStatus(getDefaultStatusCodeIfNull(response)) 
       .errorMessage(getCustomErrorMessage(response)) 
       .requestedUri(getRequestedUri(response)) <--------- HOW TO READ IT? 
       .build(); 

     return Response 
       .status(errorResponse.getHttpStatus()) 
       .type(ExtendedMediaType.APPLICATION_JSON) 
       .entity(errorResponse) 
       .build(); 
    } 
} 

Answer 1

使用

@Context 私人的HttpServletRequest的servletRequest;

並使用HttpServletRequest.getRequestURI()

public class MyExceptionMapper implements 
    ExceptionMapper<WebApplicationException> { 

    @Context 
    private HttpServletRequest servletRequest; 

    @Override 
    public Response toResponse(WebApplicationException error) { 

     Response response = error.getResponse(); 
     ErrorResponse errorResponse = ErrorResponseBuilder 
       .builder() 
       .httpStatus(getDefaultStatusCodeIfNull(response)) 
       .errorMessage(getCustomErrorMessage(response)) 
       .requestedUri(servletRequest.getRequestURI()) 
       .build(); 

     return Response 
       .status(errorResponse.getHttpStatus()) 
       .type(ExtendedMediaType.APPLICATION_JSON) 
       .entity(errorResponse) 
       .build(); 
    } 
}