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我正在按照教程進行操作,當單擊「提交」按鈕時什麼也沒有發生。我添加了一個警報來查看函數是否運行。它運行警報。未在提交按鈕上運行的Ajax腳本單擊
[代碼]
<!-- THE HTML PAGE AND JAVASCRIPT -->
<html>
<head>
<script language="JavaScript" type="text/javascript">
function ajax_post(){
// added by me to test
alert("Hello");
// Create our XMLHttpRequest object
var hr = new XMLHttpRequest();
// Create some variables we need to send to our PHP file
var url = "my_parse_file.php";
var fn = document.getElementById("first_name").value;
var ln = document.getElementById("last_name").value;
var vars = "firstname="+fn+"&lastname="+ln;
hr.open("POST", url, true);
// Set content type header information for sending url encoded variables in the request
hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
// Access the onreadystatechange event for the XMLHttpRequest object
hr.onreadystatechange = function() {
if(hr.readyState == 4 && hr.status == 200) {
var return_data = hr.responseText;
document.getElementById("status").innerHTML = return_data;
}
}
// Send the data to PHP now... and wait for response to update the status div
hr.send(vars); // Actually execute the request
document.getElementById("status").innerHTML = "processing...";
}
</script>
</head>
<body>
<h2>Ajax Post to PHP and Get Return Data</h2>
Your First Name: <input id="first_name" name="first_name" type="text" />
<br /><br />
Your Last Name: <input id="last_name" name="last_name" type="text" />
<br /><br />
<input name="myBtn" type="submit" value="Submit Data" onClick="javascript:ajax_post();">
<br /><br />
<div id="status"></div>
</body>
</html>
[PHP]
<?php
echo 'Thank you '. $_POST['firstname'] . ' ' . $_POST['lastname'] . ', says the PHP file';
?>
我在做什麼錯在這裏? 它根本不會給出任何錯誤。請幫幫我。