Objective-C：創建NSMutableDictionary或NSMutableArray

Question

對於我的iPhone應用程序，我想要管理NSMutableDictionary或NSMutableAarray中的值。

我想存儲的評價此格式

round player1 player2 
    1  6  8 
    2  7  9 
--  --  -- 

在這裏圓我的病例數將是固定值假設10，總播放器將是2，它也修復。

，但用戶可以在任何隨機順序，但在單一的按鈕click.Means

score for round "10" for both the player enter 
score for round "2" for both the player enter 

提交他們的成績因此，如何管理字典或數組，可以幫助我再次輕鬆地檢索它們？

請幫助和建議。

由於

Answer 1

//You can use combination of mutable array and dictionary to handle each round and player score 

NSMutableArray *mutArrayRound=[[NSMutableArray alloc] initWithCapacity:10]; 


//--EDIT------------------------------------------------------------------- 

//You need to do it somewhere so that it'll not give error for [mutArrayRound insertObject: atIndex:] 

mutDic=[[NSMutableDictionary alloc] init]; 

for(int i=0;i<10;i++) 
{ 
    [mutArrayRound addObject:mutDic]; 
} 

[mutDic release]; 

//------------------------------------------------------------------------- 

NSMutableDictionary *mutDic=[[NSMutableDictionary alloc] initWithCapacity:2]; 
[mutDic setValue:@"Score_Valaue" forKey:@"player1-Score"]; 
[mutDic setValue:@"Score_Valaue" forKey:@"player2-Score"]; 

//For Round1 
[mutArrayRound insertObject:mutDic atIndex:0]; 

//For Round2 
[mutArrayRound insertObject:mutDic atIndex:1]; 


/* 
    You can access for particular round using mutDic=[mutArrayRound objectAtIndex:0]; 
    And to access player score, you can use key score=[mutDic valueForKey:@"Player1_Score"]; 
*/ 

[mutArrayRound release]; 
[mutDic release]; 

Answer 2

理念1：

NSMutableDictionary* playerArounds = [NSMutableDictionary dictionary]; 
NSMutableDictionary* playerBrounds = [NSMutableDictionary dictionary]; 

[playerArounds setObject:@"5" forKey:@"1"]; 
// Player A scored 5 for round 1 

// etc... 

理念2：（合適的，如果> 2個玩家）

NSMutableArray* playerRounds = [NSMutableArray arrayWithObjects:nil]; 

for (int i=0; i<10; i++) 
    [playerRounds addObject:[NSMutableDictionary dictionary]]; 

[[playerRounds objectAtIndex:0] setObject:@"5" forKey:@"1"]; 
// Player 0 scored 5 for round 1 

// etc... 

思想3：（更純鐵C方法）

// a 2-dimensional array 
int scores[2][10]; 

scores[0][2] = 5; 

// Player 0's score for round 3 (2+1) is 5 

---

正如指出：

代替例如[playerArounds setObject:@"5" forKey:@"1"];，因爲你的價值觀將是int（而不是字符串），你最好使用（它會更有意義）：

例如[playerArounds setObject:[NSNumber numberWithInt:5] forKey:[NSNumber numberWithInt:1]];

Answer 3

您可以NSDictionary中的NSMutableArray中：

 NSMutableArray *arr = [[NSMutableArray alloc] initWithCapacity:10]; 
       // Now say Player one got 50 and Player2 got 65 in first round then add them in dictionary 


       NSDictionary *dict = [[NSDictionary alloc] initWithObjectsAndKeys:@"50",@"P1",@"65",@"P2", nil]; 
       [arr addObject:dict]; 
[dict release]; 


      // As soon as you got the sores make a NSDictionary object and init it with objects like above and add that to the mutable array . It will add it to next index. 

希望這會有所幫助。

Answer 4

爲什麼只有數組或字典是面向對象的語言？

@interface RoundResults : NSObject 

@property (nonatomic, assign) NSInteger playerOneScore; 
@property (nonatomic, assign) NSInteger playerTwoScore; 

@end 

@interface GameTotal : NSObject 

- (void)setResults: (RoundResults *)results forRound: (NSInteger)round; 
- (RoundResults *)resultsForRound: (NSInteger)round; 
- (NSUInteger)countOfResults; 

@end