mysql> create table cars(car_id int auto_increment primary key, model
varchar(50), model_id int);
Query OK, 0 rows affected (0.01 sec)
mysql> create table models(model_id int auto_increment primary key, name
varchar(50));
Query OK, 0 rows affected (0.01 sec)
mysql> insert into models(name) VALUES ('Taurus'), ('Ka'), ('Mustang');
Query OK, 3 rows affected (0.00 sec)
Records: 3 Duplicates: 0 Warnings: 0
mysql> insert into cars(model) VALUES ('Ka'), ('Mustang'), ('Taurus'),
('F150');
Query OK, 4 rows affected (0.00 sec)
Records: 4 Duplicates: 0 Warnings: 0
mysql> select * from cars;
+--------+---------+----------+
| car_id | model | model_id |
+--------+---------+----------+
| 1 | Ka | NULL |
| 2 | Mustang | NULL |
| 3 | Taurus | NULL |
| 4 | F150 | NULL |
+--------+---------+----------+
4 rows in set (0.00 sec)
mysql> select * from models;
+----------+---------+
| model_id | name |
+----------+---------+
| 1 | Taurus |
| 2 | Ka |
| 3 | Mustang |
+----------+---------+
3 rows in set (0.00 sec)
mysql> update cars,models set cars.model_id = models.model_id
where models.name = cars.model;
Query OK, 3 rows affected (0.06 sec)
Rows matched: 3 Changed: 3 Warnings: 0
mysql> select * from cars;
+--------+---------+----------+
| car_id | model | model_id |
+--------+---------+----------+
| 1 | Ka | 2 |
| 2 | Mustang | 3 |
| 3 | Taurus | 1 |
| 4 | F150 | NULL |
+--------+---------+----------+
4 rows in set (0.03 sec)
你只是問如何正確使用'模型id'字段填充'汽車'表或其他?目前尚不清楚。 – Alnitak 2008-11-11 10:16:50