我通過網絡進行了一些研究,並找到了一些有用的代碼。我改了一點,在試圖捕捉整個屏幕,併產生我可以通過UDP數據包發送緩衝區:屏幕捕獲無法使用C++和GDI捕獲整個屏幕
#include <iostream>
#include <Windows.h>
#include <fstream>
void CapruteScreenAndSaveToFile()
{
uint16_t BitsPerPixel = 24;
uint32_t Width = GetSystemMetrics(SM_CXSCREEN);
uint32_t Height = GetSystemMetrics(SM_CYSCREEN);
// Create Header
BITMAPFILEHEADER Header;
memset(&Header, 0, sizeof(Header));
Header.bfType = 0x4D42;
Header.bfOffBits = sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER);
// Create Info
BITMAPINFO Info;
memset(&Info, 0, sizeof(Info));
Info.bmiHeader.biSize = sizeof(BITMAPINFOHEADER);
Info.bmiHeader.biWidth = Width;
Info.bmiHeader.biHeight = Height;
Info.bmiHeader.biPlanes = 1;
Info.bmiHeader.biBitCount = BitsPerPixel;
Info.bmiHeader.biCompression = BI_RGB;
Info.bmiHeader.biSizeImage = Width * Height * (BitsPerPixel > 24 ? 4 : 3);
// Capture screen and save to Pixels
char* Pixels = NULL;
HDC MemDC = CreateCompatibleDC(0);//Context);
HBITMAP Section = CreateDIBSection(MemDC, &Info, DIB_RGB_COLORS, (void**)&Pixels, 0, 0);
DeleteObject(SelectObject(MemDC, Section));
BitBlt(MemDC, 0, 0, Width, Height, GetDC(0), 0, 0, SRCCOPY);
DeleteDC(MemDC);
// Concatenate everything
char * buffer = (char*)malloc(sizeof(Header) + sizeof(Info.bmiHeader) + (((BitsPerPixel * Width + 31) & ~31)/8) * Height);
memcpy(buffer, (char*)&Header, sizeof(Header));
memcpy(buffer + sizeof(Header), (char*)&Info.bmiHeader, sizeof(Info.bmiHeader));
memcpy(buffer + sizeof(Header) + sizeof(Info.bmiHeader), Pixels, (((BitsPerPixel * Width + 31) & ~31)/8) * Height);
// Save to file
std::fstream hFile("Foo.bmp", std::ios::out | std::ios::binary);
hFile.write(buffer, sizeof(Header) + sizeof(Info.bmiHeader) + (((BitsPerPixel * Width + 31) & ~31)/8) * Height);
// Clean up
hFile.close();
DeleteObject(Section);
free(buffer);
}
int main()
{
CapruteScreenAndSaveToFile();
return 0;
}
但似乎只捕捉到我的桌面,這部分:
即使我使用CreateCompatibleDC(0)。
我測試你的代碼在我的電腦上。它工作正常。生成的「bmp」具有全屏捕獲功能。 – Naidu
不要忘記有[SetWindowDisplayAffinity](https://msdn.microsoft.com/en-us/library/windows/desktop/dd375340.aspx)以及OpenGL。兩者都可能成爲您的代碼的障礙,並使其失敗。不是你想要解決的問題,而是你不可避免會遇到的問題。 – IInspectable