Symfony console.exception不會觸發監聽器

Question

我正在運行Symfony 2.7.6 dev，並且我有一個應該在console.exception上觸發的監聽器，但它不會觸發，它只會在控制檯中顯示異常照常。出於測試目的，我已經合併了一個console.terminate監聽器，它工作正常。 （我也測試了console.command，這也很好）。

對於我的生活，我無法弄清楚爲什麼console.exception事件不會觸發或爲什麼console.exception監聽器不觸發。在config.yml

ConsoleExceptionListener設置

kernel.listener.command_dispatch: 
     class: CompanyHidden\PortalBundle\Listener\ConsoleExceptionListener 
     arguments: ["@service_container", "@router"] 
     tags: 
      - { name: kernel.event_listener, event: console.exception, method: onConsoleException } 
      - { name: kernel.event_listener, event: console.terminate, method: onConsoleTerminate } 

ConsoleExceptionListener.php

<?php 

namespace CompanyHidden\PortalBundle\Listener; 

use Symfony\Component\HttpKernel\Event\GetResponseForExceptionEvent; 
use Symfony\Component\HttpFoundation\Response; 
use Symfony\Component\HttpFoundation\RedirectResponse; 
use Symfony\Component\Console\Event\ConsoleExceptionEvent; 
use Symfony\Component\DependencyInjection\ContainerInterface; 
use Symfony\Bundle\TwigBundle\TwigEngine; 
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Template; 

class ConsoleExceptionListener 
{ 
    private $container; 
    private $router; 

    function __construct($container, $router) 
    { 
     $this->container = $container; 
     $this->router = $router; 
    } 

    public function onConsoleTerminate() 
    { 
     die(">>>> TERMINATE TEST >>>>"); 
    } 

    public function onConsoleException(ConsoleExceptionEvent $event) 
    { 
     die(">>> EXCEPTION TEST<<<<"); 
    } 
} 

控制檯命令

<?php 
namespace CompanyHidden\PortalBundle\Command; 

use Symfony\Bundle\FrameworkBundle\Command\ContainerAwareCommand; 
use Symfony\Component\Console\Input\InputArgument; 
use Symfony\Component\Console\Input\InputInterface; 
use Symfony\Component\Console\Input\InputOption; 
use Symfony\Component\Console\Output\OutputInterface; 

use CompanyHidden\PortalBundle\Classes\ImapMailbox; 

class getEmailsCommand extends ContainerAwareCommand 
{ 
    protected function configure() 
    { 
     $this->setName('getEmails'); 
    } 

    protected function execute(InputInterface $input, OutputInterface $output) 
    { 
     $context = $this->getContainer()->get('router')->getContext(); 
     $context->setScheme('http'); 

     # SIMULATED TERMINATION TEST 
     //print ">>>> TERMINATED <<<<<\n"; 
     //return null; 

     # SIMULATED EXCEPTION TEST 
     $null = null; 
     $null->getNull(); 

     //..... Rest of Code, not relevant 
    } 
} 
?> 

時拋出（而不是引發異常監聽器）控制檯異常

Answer 1

試圖通過這種方式來建立你的控制檯聽衆：

namespace CompanyHidden\PortalBundle\Listener; 

use Symfony\Component\EventDispatcher\EventSubscriberInterface; 
use Symfony\Component\Console\Event\ConsoleTerminateEvent; 
use Symfony\Component\Console\Event\ConsoleExceptionEvent; 
use Symfony\Component\Console\ConsoleEvents; 

class ConsoleExceptionListener implements EventSubscriberInterface 
{ 
    /.../ 

    public static function getSubscribedEvents() 
    { 
     return [ 
      ConsoleEvents::EXCEPTION => 'onConsoleException', 
      ConsoleEvents::TERMINATE => 'onConsoleTerminate' 
     ]; 
    } 

    public function onConsoleTerminate(ConsoleTerminateEvent $event) 
    { 
     die(">>>> TERMINATE TEST >>>>"); 
    } 

    public function onConsoleException(ConsoleExceptionEvent $event) 
    { 
     die(">>> EXCEPTION TEST<<<<"); 
    } 
} 

Answer 2

在控制檯文件，啓動與$內核內核級>啓動（）;

$kernel = new AppKernel($env, $debug); 
$application = new Application($kernel); 
$kernel->boot(); 

$kernel->getContainer()->get('event_dispatcher')->addListener(\Symfony\Component\Console\ConsoleEvents::COMMAND, 
    function (\Symfony\Component\Console\Event\ConsoleCommandEvent $event) { 
     var_dump("COMMAND EVENT"); 
    }); 

$kernel->getContainer()->get('event_dispatcher')->addListener(\Symfony\Component\Console\ConsoleEvents::EXCEPTION, 
    function (\Symfony\Component\Console\Event\ConsoleExceptionEvent $event) { 
     var_dump("EXCEPTION EVENT"); 
    }); 

$kernel->getContainer()->get('event_dispatcher')->addListener(\Symfony\Component\Console\ConsoleEvents::TERMINATE, 
    function (\Symfony\Component\Console\Event\ConsoleTerminateEvent $event) { 
     var_dump("TERMINATE EVENT"); 
    }); 


$application->run($input); 

Answer 3

Scoolnico的解決方案與symfony 3.3完美配合。 有關信息，'console.exception'事件已被替換爲symfony 3.3中的'console.error'（https://symfony.com/blog/new-in-symfony-3-3-better-handling-of-command-exceptions）