3
我想了解如何使用firebug來調試我的Javascript。所以我有下面列出的HTML。我想在var的''上設置一個監視表達式。我去了螢火蟲的腳本選項卡,打開監視窗格,進入小號成說:「新腕錶表達」的區域。在Firebug中設置手錶表達式:ReferenceError - s沒有定義
我得到一個錯誤:
ReferenceError: s is not defined
爲什麼?
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<style type="text/css">
.StateOne .InitiallyHidden { display: none; }
.StateTwo .InitiallyVisible { display: none; }
</style>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script>
<script language="javascript" type="text/javascript">
$(document).ready(function()
{
$('.x').click(function() {
var s = $("#StateContainer")[0];
s.className = (s.className == 'StateOne' ? 'StateTwo' : 'StateOne');
});
});
</script>
</head>
<body>
<button class="x">Change StateContainer</button>
<div class="StateOne" id="StateContainer">
<div class="InitiallyVisible">Visible first</div>
<div class="InitiallyHidden">Visible second</div>
<div class="InitiallyVisible">Visible first</div>
<div class="InitiallyHidden">Visible second</div>
<div class="InitiallyVisible">Visible first</div>
<div class="InitiallyHidden">Visible second</div>
<div class="InitiallyVisible">Visible first</div>
<div class="InitiallyHidden">Visible second</div>
</div>
</body>
</html>