每年自動更改的年齡

Question

可能重複：
How to change the age automatically every year

我寫了這個程序，但我有一個變量 「年齡」。我該如何做到這一點，以便我不必每年都改變狗的年齡？換句話說，它應該自動改變？

#include <iostream> 
#include <conio.h> 
#include <string> 
#include <stdlib.h> 

using namespace std; 

class Dog//instance class 
{ 
string Fam; 
string & Name; 
//string Name; 
string Otch; 
static string mField; 
unsigned int Nagradi; 
unsigned int Age; 
public: 

Dog(string fam="", string otch="", string nam="", 
unsigned nagradi=0, unsigned age=0):Fam("") 
    ,Name(Fam) 
{ 
    cout << "Dog::Dog(" << nam << ")" << endl; 
    Name = nam; 
    Otch = otch; 
    Fam = fam; 
    Nagradi = nagradi; 
    Age = age; 
} 

Dog(Dog const & st): Name(Fam)//constructor 
{ 
    cout << "Dog::Dog(copy:" << st.Name << ")" << endl; 
    Name = st.Fam; 
    Otch = st.Name; 
    Fam = st.Otch; 
    Nagradi = st.Nagradi; 
    Age = st.Age; 
} 

~Dog()//Destructor 
{ 
    cout << "Dog::~Dog(" << Name << ")" << endl; 
    system ("pause"); 
     } 

void Show() 
{ 
    cout<< Name << ' ' << Fam << ' ' << Otch << 
      " #" << Nagradi << " age:" << Age << endl; 
} 
}; 

Answer 1

存儲出生日期而不是年齡，然後計算你需要它的年齡。

就像有人說你上次問這個問題。請不要再問同一個問題兩次。