嘿這裏大家是我的代碼:集成類
這裏是我的集成類:
package Chapter5;
/*Author: Cory Zander
* Purpose: Find the area and volume between two curves
*/
public class Integration
{
static double x;
static double dx;
static double f, g;
static double sumg = 0;
static double sumf = 0;
public static double f(double x)
{
f = x * Math.exp(x);
return x;
}
public static double g(double x)
{
g = Math.pow(x, 2);
return x;
}
public static double Areaf(double lower, double upper)
{
int i;
x = lower;
dx = (upper - lower)/2000;
for(i = 0; i <= 2000; i++)
{
if(i == 0 || i == 2000)
{
sumf += f;
}
else
{
sumf += 2 * f;
}
x += dx;
}
sumf *= dx/2;
return sumf;
}
public static double Areag(double lower, double upper)
{
int i;
x = lower;
dx = (upper - lower)/2000;
for(i = 0; i <= 2000; i++)
{
if(i == 0 || i == 2000)
{
sumg += g;
}
else
{
sumg += 2 * g;
}
x += dx;
}
sumg *= dx/2;
return sumg;
}
好吧,我剛剛編輯這個固定的areaf和areag問題,但由於某些原因,當我得到的f曲線下的區域仍然得到0.爲什麼它沒有采取積分類的sumf
我在回答中寫了你該怎麼做,不是嗎?您的更改不正確。如果你不明確地調用這些方法,你的總和將總是'0'。 – bellum
您的權利我沒有在您的評論中看到Integration.Areaf部分。謝謝 – CraZieR
隨着我上面得到的代碼,什麼是調用方法的最佳方式,我只是有點困惑 – CraZieR