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我試圖從Rails的升級我的應用程序2.3.4 2.3.8 ..提升的Rails 2.3.4從2.3.8到問題
我走進environment.rb文件中,並改變
RAILS_GEM_VERSION = '2.3.4' unless defined? RAILS_GEM_VERSION
到
RAILS_GEM_VERSION = '2.3.8' unless defined? RAILS_GEM_VERSION
(做我需要做別的東西嗎?)
我一個米使用MySQL服務器版本:我不使用捆綁
我運行在OS 5.1.47
X 10.6.6
這裏是我的database.yml,這符合我的工作應用程序我在2.3.8創建(而不是升級)
development:
adapter: mysql
encoding: utf8
reconnect: false
database: _development
pool: 5
username: root
password:
socket: /tmp/mysql.sock
當我做到這一點,任何頁面加載我給..同樣的錯誤可以通過試圖建立能夠得到同樣的錯誤/從數據庫中檢索模型,錯誤是th是:
>> Company.new
NoMethodError: undefined method `retrieve_connection' for nil:NilClass
from /Library/Ruby/Gems/1.8/gems/activesupport-2.3.8/lib/active_support/whiny_nil.rb:52:in `method_missing'
from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.8/lib/active_record/connection_adapters/abstract/connection_specification.rb:123:in `retrieve_connection'
from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.8/lib/active_record/connection_adapters/abstract/connection_specification.rb:115:in `connection'
from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.8/lib/active_record/base.rb:1301:in `columns'
from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.8/lib/active_record/base.rb:3055:in `attributes_from_column_definition_without_lock'
from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.8/lib/active_record/locking/optimistic.rb:66:in `attributes_from_column_definition'
from /Library/Ruby/Gems/1.8/gems/activerecord-2.3.8/lib/active_record/base.rb:2469:in `initialize'
from (irb):1:in `new'
from (irb):1
編輯:從environment.rb中
config.gem "authlogic"
config.gem "hpricot"
config.gem "BlueCloth", :lib => 'bluecloth'
config.gem "daemons"
config.gem "gravtastic", :version => '2.2.0'
config.gem "json"
config.gem "ruby-rapleaf"
config.gem "ar-extensions"
config.gem "url_shortener"
config.gem 'aws-s3', :version => '>= 0.6.2', :lib => 'aws/s3'
config.gem 'paperclip', :version => '>= 2.3.1.1'
config.gem 'omniauth'
這是類似的:http://stackoverflow.com/questions/2892977/updating-rails-to-2-3-6 - 你可以發佈你的寶石在你的application.rb? –
這很可能是問題所在。寶石通常在environment.rb中指定,發佈它的內容。 – jonnii
更新了我的問題 – Rabbott