增量插入到SQL列中

Question

我有帶日期列的表。我想插入整數：從第一個星期一到星期日1，從第二個星期一到星期日2等...

我該如何在SQL服務器中執行此操作？

預期輸出：

03/14/16 1 
03/15/16 1 
03/16/16 1 
03/17/16 1 
03/18/16 1 
03/19/16 1 
03/20/16 1 
03/21/16 2 
03/22/16 2 
03/23/16 2 
03/24/16 2 
03/25/16 2 
03/26/16 2 
03/27/16 2 
03/28/16 3 
03/29/16 3 
03/30/16 3 
03/31/16 3 
04/01/16 3 
04/02/16 3 
04/03/16 3 
04/04/16 4 

Answer 1

試試這個

SELECT DENSE_RANK() OVER(ORDER BY DATEPART(YEAR,[date column]) 
,DATEPART(WEEK,[date column])) FROM table 

Answer 2

做一樣DENSE_RANK

的另一種方式，您可能還需要SET DATEFIRST 1如果區域不具備週一一週中的第一天。

SELECT 
MyDate, 
DATENAME(WEEKDAY, MyDate), 
(DATEPART(WEEK, MyDate) - DATEPART(WEEK,MIN(MyDate) OVER (ORDER BY MyDate))) 
+ ((DATEPART(YEAR, MyDate) - DATEPART(YEAR,MIN(MyDate) OVER (ORDER BY MyDate))) *52) + 1 MyWeek 
FROM MyData 

MyDate         MyWeek 
---------- ------------------------------ ----------- 
2015-12-26 Saturday      1 
2015-12-27 Sunday       1 
2015-12-28 Monday       2 
2015-12-29 Tuesday      2 
2015-12-30 Wednesday      2 
2015-12-31 Thursday      2 
2016-01-01 Friday       2 
2016-01-02 Saturday      2 
2016-01-03 Sunday       2 
2016-01-04 Monday       3 
2016-01-05 Tuesday      3 

編輯修復一年交叉

編輯2真正解決一年道口，每個星期一的增量計數器（例如，如果第一次約會是週中），見示例數據。

Answer 3

DECLARE @start DATE = '2016-03-14' 

;WITH cte AS (
SELECT @start as [d], 
     1 as [w] 
UNION ALL 
SELECT DATEADD(day,1,[d]), 
     CASE WHEN DATEPART(WEEK,[d]) != DATEPART(WEEK,DATEADD(day,1,[d])) THEN w+1 ELSE w END 
FROM cte 
WHERE d < '2017-04-04') 


SELECT [d], [w] 
FROM cte 
OPTION (MAXRECURSION 1000)