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我試圖用collection.find
collection.find({})不返回的NodeJS收集記錄
var DTX = mongoose.models.dtx;
var detx = DTX.find({});
來從一個集合中的所有記錄,但是,當我console.log(detx)
,它給了我如下的迴應:
{ _mongooseOptions: {},
mongooseCollection:
{ collection:
{ db: [Object],
collectionName: 'dtx',
internalHint: null,
opts: {},
slaveOk: false,
serializeFunctions: false,
raw: false,
pkFactory: [Object],
serverCapabilities: undefined },
opts: { bufferCommands: true, capped: false },
name: 'ddtx',
conn:
{ base: [Object],
collections: [Object],
models: [Object],
replica: false,
hosts: null,
host: 'localhost',
port: 27017,
user: undefined,
pass: undefined,
name: 't23',
options: [Object],
otherDbs: [],
_readyState: 1,
_closeCalled: false,
_hasOpened: true,
_listening: true,
_events: [Object],
db: [Object] },
queue: [],
buffer: false },
model:
{ [Function: model]
base:
{ connections: [Object],
plugins: [],
models: [Object],
modelSchemas: [Object],
options: [Object],
dbConnected: true },
modelName: 'dtx',
model: [Function: model],
.....
}
.....
}
.....
}
我讀了幾個帖子,然後我意識到在nodejs
這返回cursor
。那麼我嘗試如下:
var detx=DTX.find({},function(err,cursor){
cursor.each(err,item){
return item;
});
});
這也沒有幫助。如何在沒有任何條件的情況下從集合中獲取所有記錄作爲array
?
@RolandStarke ..嗯,我希望這AINT這種情況下。隨着'query' PARAMS傳遞給'find',它會給我的數據,但不是空.. –