將變量更新到sqlite

Question

我試圖將變量更新到sqlite3數據庫中。該查詢是在sqlite瀏覽器中工作，但當我想通過我的網絡進行更新時，它給了我'致命錯誤：調用成員函數對非對象的execute（）'。

Code: 
$DB = new PDO('sqlite:database/Sample.sqlite3'); 
$No = 1; 
$Name = 'John'; 
$RecordNo = 2; 
$statement ="update Sample set No =".$No.", Name='".Name."', Date='2012-05-14' where RecordNo=".$RecordNo; 
$update = $DB->prepare($statement); 
$update->execute(); 

致命錯誤在'$ update-> execute（）;''語句中。它應該執行，因爲沒有語法錯誤或代碼。好心提醒。

Answer 1

另...

<?php 
$DB = new PDO('sqlite:database/Sample.sqlite3'); 
/* Execute a prepared statement by passing an array of insert values */ 
$No = 1; 
$Name = 'John'; 
$RecordNo = 2; 
$sth = $dbh->prepare('update sample set No=? Name=? Date='2012-05-14' where Recordno =?'); 
$sth->execute(array($No, $Name,$RecordNo)); 
?>