-1
我有以下代碼,猜測字符串不會被替換出於某種原因,如果我嘗試手動agreements.replace('{customername}', 'some string');
一切工作正常。字符串替換回路
var keywords = [
{
key: '{customername}',
desc: 'Customer Name',
map: 'user_name'
},
{
key: '{vesselname}',
desc: 'Customer Vessel Name',
map: 'vessel_name'
}
];
var parseData = {
user_name: "Some name",
vessel_name: "Some Vessel",
spot_title: "My Spot",
today: new Date().toDateString()
};
var agreements = "{customername}, some customer, {vesslname} -> here";
for(var i = 0; i < keywords.length; i++) {
console.log(keywords[i]['key'], parseData[keywords[i]['map']]);
agreements.replace(
keywords[i]['key'],
parseData[keywords[i]['map']]
);
}
alert(agreements);
請忽略我加入一些細節,以及計算器使得它的要求,有趣的......
'.replace'返回新的字符串,不會替換原始字符串。把它分配回 – Rajesh
@Rajesh哦,來吧,呵呵。 =) – dud3
@Rajesh謝謝,這只是工作。 – dud3