Python更改整個列表的類型？

Question

我願做這樣的事情

def foo(x,dtype=long): 
    return magic_function_changing_listtype_to_dtype(x) 

即充滿INT

任何簡單的方法來做到這一點對嵌套列表全海峽的名單列表，即改變類型[」 1 ']，[2' ']] - > INT

Answer 1

map(int, ['1','2','3']) # => [1,2,3] 

這樣：

def foo(l, dtype=long): 
    return map(dtype, l) 

Answer 2

str_list = ['1', '2', '3'] 
int_list = map(int, str_list) 
print int_list # [1, 2, 3] 

件

Answer 3

def intify(iterable): 
    result = [] 
    for item in iterable: 
     if isinstance(item, list): 
      result.append(intify(item)) 
     else: 
      result.append(int(item)) 
    return result 

作品任意深度嵌套的列表：

>>> l = ["1", "3", ["3", "4", ["5"], "5"],"6"] 
>>> intify(l) 
[1, 3, [3, 4, [5], 5], 6] 

Answer 4

列表理解應該這樣做：

a = ['1','2','3'] 
print [int(s) for s in a] # [1, 2, 3]] 

嵌套：

a = [['1', '2'],['3','4','5']] 
print [[int(s) for s in sublist] for sublist in a] # [[1, 2], [3, 4, 5]] 

Answer 5

這裏是一個相當簡單的遞歸函數轉換任何深度的嵌套列表：

def nested_change(item, func): 
    if isinstance(item, list): 
     return [nested_change(x, func) for x in item] 
    return func(item) 

>>> nested_change([['1'], ['2']], int) 
[[1], [2]] 
>>> nested_change([['1'], ['2', ['3', '4']]], int) 
[[1], [2, [3, 4]]] 

Answer 6

a=input()#taking input as string. Like this-10 5 7 1(in one line) 
a=a.split()#now splitting at the white space and it becomes ['10','5','7','1'] 
#split returns a list 
for i in range(len(a)): 
    a[i]=int(a[i]) #now converting each item of the list from string type 
print(a) # to int type and finally print list a