將字符串列表轉換爲字符串數組

Question

我有一個字符串列表，其中每個字符串基本上都是從.csv程序拉入的一行數據。 例如：

data[0] = '2014-01-31,46.83,48.55,46.80,48.03,3414400,48.03' 

data[1] = '2014-01-30,47.47,48.11,47.29,48.00,2083900,48.00' 

...等等。

我想這轉化爲AA二維列表這樣的：

newData[0][0] = '2014-01-31' 
newData[0][0] = '2014-01-30' 
newData[1][0] = '46.83' 
newData[1][1] = '47.47' 

...等

也就是說，我想拆每個,琴絃，但使用時，我試圖data.split(",")它不想這樣做，因爲它是一個列表。有任何想法嗎？

Answer 1

在列表中的項目應用str.split：

newData = [item.split(',') for item in data] 

演示：

>>> data = ['2014-01-31,46.83,48.55,46.80,48.03,3414400,48.03', '2014-01-30,47.47,48.11,47.29,48.00,2083900,48.00'] 
>>> newData = [item.split(',') for item in data] 
>>> newData[0][0] 
'2014-01-31' 
>>> newData[1][0] 
'2014-01-30' 

正如其他人所指出的，你應該使用csv模塊從一個CSV文件中讀取數據，考慮到該文件包含：

2014-01-31,46.83,48.55,46.80,48.03,3414400,48.03 
2014-01-30,47.47,48.11,47.29,48.00,2083900,48.00 

此代碼將得到所需要的輸出：

import csv 
with open('file.csv') as f: 
    reader = csv.reader(f) 
    data = list(reader)