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我有URI地址，基本上是試圖在html頁面上顯示圖像。該html頁面只顯示一個空的圖像。我真的不知道該怎麼做，因爲我是Android和Django的初學者。這裏是我的代碼：如何從Android SD卡上傳圖片到Django服務器？
Android Studio代碼。我在做我的樣本Java文件包的新文件：
public class ImageHTTPPostRequest
{
public void doFileUpload(String path){
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String lineEnd = "\r\n";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://127.0.0.1:8000/"; // server ip
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(CameraIntentActivity.photoUriPath));
// open a URL connection to the Servlet
URL url = new URL("http://127.0.0.1:8000/");
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+" ");
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + path + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(lineEnd);
// close streams
Log.e("Debug", "File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream (conn.getInputStream());
String str;
while ((str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
}
}
}
這裏是我的Django代碼：
views.py
def imageUpload(request):
form = PhotoForm(request.POST, request.FILES)
if request.method=='POST':
if form.is_valid():
image = request.FILES['photo']
new_image = Photo(photo=image)
new_image.save()
response_data=[{"success": "1"}]
return HttpResponse(simplejson.dumps(response_data), mimetype='application/json')
forms.py
class PhotoForm(forms.Form):
uploadImage = forms.FileField(label='uploadImage')
模型.py
class Photo(models.Model):
user = models.CharField(max_length=5000)
photo = models.FileField(upload_to='memorylane/static/images')
uploaded = models.DateTimeField(auto_now_add=True)
modified = models.DateTimeField(auto_now=True)
def __unicode__(self):
return '%s' % self.title
然後是html頁面。我真的不知道有什麼在這裏：
<!DOCTYPE html>
<html lang="en">
{% load staticfiles %}
{% include 'head.html' %}
<head>
\t <title>Image Upload</title>
\t <style>
\t </style>
</head>
<body>
\t <img class="uploadImage" src="placeholder" width="500" height="500">
</body>
</html>謝謝！
請註明你所面對的問題，即任何異常發生或代碼不工作？ – VVJ
當我運行html頁面imageUpload時，它說：視圖沒有返回一個HttpResponse對象。它返回None而不是。 – aquaelmo
設置內容類型不是MIME類型 – VVJ