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我想從字符串創建豆,但無法創建,因爲它是返回null.Here輸入StringReader創建空的對象是我的代碼使用的JAXBContext
public ModelAndView checkPhotoQualityRequest(
@RequestBody String photoDataXml, HttpServletRequest request) {
PhotoQuality photoQuality = null;
try {
JAXBContext jaxbContext = JAXBContext
.newInstance(PhotoQuality.class);
Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
StringReader reader = new StringReader(photoDataXml);
photoQuality = (PhotoQuality) unmarshaller.unmarshal(reader);
PhotoQuality.java
package in.gov.uid.opencvaccess.bean;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;
@XmlType(name = "PhotoQuality")
@XmlRootElement(name = "PhotoQuality")
public class PhotoQuality {
private String photoid;
private byte[] photo;
private boolean quality;
private String message;
public String getMessage() {
return message;
}
public void setMessage(String message) {
this.message = message;
}
public String getPhotoid() {
return photoid;
}
public void setPhotoid(String photoid) {
this.photoid = photoid;
}
public byte[] getPhoto() {
return photo;
}
public void setPhoto(byte[] photo) {
this.photo = photo;
}
public boolean isQuality() {
return quality;
}
public void setQuality(boolean quality) {
this.quality = quality;
}
}
請幫我解決這個問題。當我調試和檢查bean它顯示所有空值,但photoDataXml顯示完整的XML。
什麼樣的XML看起來像你試圖解組。如果你填充你的對象模型,然後編組它,它是如何比較你正試圖解組的XML? –